Calculus 1: Limits & Derivatives (24 of 27) Finding the Limits of a Function - Example 11

In this video I will calculate the limit(x approaches infinity) of cos(x).

Next video in the series can be seen at:

[haidashira]

I believe that some math teachers enjoy bringing such examples in tests in order to trick the students.
Now, it's much harder for math teachers to trick me, thanks to you professor. :D

[mrmillmill]

Incredible instruction! at 1:20 you mention the "funneling effect where the value zero's in to a particular amount then you say that is not happening...you say since we don't get down to a smaller and smaller range as things are changing we can say therefore safely there is no limit for this particular function" are you reiterating that no matter the increasing value of x the function will always remain within positive one or negative one? Whereas if a limit existed the function would converge on a certain value? I just wanted to make sure I wasn't missing something.

[saifawan]

if we mention that the infinity is positive or negative!! then what will be the solution??

[rubenalejandrolomelirodrig]

Evaluate for please:
lim x→∞ 5x cos x

[golmolenahisidhibaatein]

thanks sir.
but we have [zero integral to infinity sinpx dx]
q1)Is it's enough to write as (-cos px /p) in the limits of 0 to infinity
no need of apply limits to -cospx/p.
sir pls reply.

[babitarawat]

so can we consider cos(x) as a constant

[chrismusix]

I guess I'm surprised the math heads don't consider 1 and -1 to be the actual limits, as those two values do have an asymptotic character in this regard. I understand 1 and -1 may not fulfill the strictest definition of a mathematical limit, but they still do have a limiting quality here.