filmov
tv
If r= xî+yĵ+zk̂, prove that divr= 3 , div(r/r³)= 0 and curl r= 0 | Divergence and Curl of a Vector
Показать описание
I hope u enjoyed the video and learnt something. Do share your queries, doubts, suggestions and other things in the comments section.
Also, check similar videos on my channel or ask for the same if you can't find it.
If you find any error in the question, solution, concept or in the explanation do mention that out in comments as well.
Here's a list of my popular Playlists↓
Engineering Mathematics ↓↓
Previous Year Questions Examwise:
Thanks.
Happy Learning!
Also, check similar videos on my channel or ask for the same if you can't find it.
If you find any error in the question, solution, concept or in the explanation do mention that out in comments as well.
Here's a list of my popular Playlists↓
Engineering Mathematics ↓↓
Previous Year Questions Examwise:
Thanks.
Happy Learning!
If r= xî+yĵ+zk̂, then prove grad(1/r)= -r/r³ and grad(rⁿ)= n r^(n-2) r | Vector Calculus
If r= xî+yĵ+zk̂, prove that divr= 3 , div(r/r³)= 0 and curl r= 0 | Divergence and Curl of a Vector...
If r is the position vector given by r=xi ̂+yj ̂+zk ̂, then divergence of unit vector r ̂ is (Full)...
If r is the position vector given by r =xi ̂+yj ̂+zk ̂, then ∇ (r^n ) is (a) nr^(n-1) r ̂
If r= xî+yj+zk, prove that div(r/r³)= 0. Divergence and Curl of a Vector_Mohammad_2023
If r is the position vector given by r=xi ̂+yj ̂+zk ̂, then ∇.(r/r^3 ) is (a) -3 (b) 0 (c) 1 (d) 3...
If r is the position vector given by r=xi ̂+yj ̂+zk ̂, then divergence of unit vector r ̂ (trick)...
If r is the position vector given by r=xi ̂+yj ̂+zk ̂, then the gradient of (1/r^3 ) is given by
For a position vector r = xi+yj+zk | Prove that - div(r^n r) = ( n+3 ) r^n | Bhagvati classes
find div (r^n r ) | find the value of n for which r^n r is solenoid | Vector Calculus | POTENTIALG
verify div r=3 , where r=xi+yj+zk
#1.12 a=r=xi+yj+zk [Vector Lines of a Radius Vector]
Problem on vector differential operator
Proving the Divergence of Position Vector r = xi^ + yj^ + zk^ is Equal to 3 | Bhagvati classes
If r= x i+ y j+ z k then grad( log(mod(r)))=?
P-67.If vector r =x.i+y.j+z.k , prove that vector r=(r. i) i + (r. j) j + (r. k) k
if r= | r| where, r =x i+y j +z k then prove that div f(r) =f'(r) .del r |Divergence Curl Grad...
If a is a constant vector, then ∇ ×(a ×r ): (a) 0 (b) a (c) 2a (d) a/2
If r is a vector and r = xi + yj + zk and a is a constant vector, find the value of curl(r x a).
If u= x²-y²+z² and V vector = xi+yj+zk then del.(u Vvector) = ?
For a position vector r = xi^ + yj^ + zk^ show that curl(k^/r) = -yi^ + xj^\r^3 | Bhagvati classes
For a position vector r = xi^ + yj^ + zk^ show that curl(r/r^3) = 0 | Vector space | Bhagvati clas
Application of del ( divergence) and gradient
Show that Grad r^n = nr^(n - 2) r ,where r= Xi+Yj+Zk//Gradient of scalar Function
Комментарии