Limits and Derivatives One Shot Maths | Class 11 Maths NCERT Explanation & Solution with Ushank Sir

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Limits and Derivatives One Shot Maths | Class 11 Maths NCERT Explanation & Solution with Ushank Sir

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[foxtrotgaming]

mistake found in x⁴-81/2x²-5x-3
Sir in x+3
3+3 = 6 not 9

[gwsatyam]

16:26 Dear Ushank sir with respect
Sir, x+3=6 hoga so final answer will be 108/7 not 162/7 . Please pay attention
Thankyou Sir

[seh]

16:28 Sir, apne 18×9 kar diye he, par question me toh 18×6 hona chahiye

(x²+9) (x+3)
(3²+9) (3+3)
(9+9) (6) = 108

Toh uska answer *108/7* hona chahiye

[shauryasahu]

4 ghante baad exam h... 2 lecture dekhna h... 😎😎
Ncert karna h...
Confidence exosphere me h... 😎
Kvian...

[SudhanshuJha-cioq]

You teaching style is very nice 👍.VOTE for derivatives 😅

[Aditya_km]

12th class students clearing backlog ☠️
Attendance here🫂

[Nitesh-rlbj]

Es video ke mistakes
16:28
53:56
26:04

[gangalahripareek]

16:20 Sir 3+3=6 hoga and answer 108/7 ayega [KOI NI HOJATA HAI]

[AnkitBharti-sdso]

Kisne 11th class mai limits and derivatives nhi padha tha jo aab vapas aaya h 12th mai ye video dekhne😂😂

[Fact_boy_-k]

Ma kasam jis jis se like or subscribe nhi kiya wo pakka exam mak fail😢

[saptarshighosh]

34:00 also, break x^10 - 1 => (x^5 + 1)(x^5 -1), x^15 -1 => (x^5)^3 - 1^3, then apply rule.

[Tinky_plays_]

Bro's calculation is faster than any super car....!! 😭🤌

[Abhishekkumar-yxv]

Cosec (0) = not defined sir ! Not zero 28:41

[swastikkandpal]

Sir at 17:57 u wrote that 0/0 is 0, which is wrong ❌ since Enything divided by 0 is not defined till now...
I don't think I'll get attention, but still m writing this for my self satisfaction 😂

[sonymishra]

16:22 pr mistake hai 3+3 is not equal to 9 (3+3=6)

[collegestar]

Kis kisko lagta hai ashu sir ka judwa hai😂😂😂😂😂😂😂

[Armaan_GG]

At 16:29 Correct solution is given below lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3)

1. Find the derivatives of the numerator and denominator:
f(x) = x^4 - 81
g(x) = 2x^2 - 5x - 3

f'(x) = 4x^3
g'(x) = 4x - 5

2. Evaluate the limit of the ratio of the derivatives:
lim (x -> 3) (f'(x) / g'(x)) = 108 / 7

3. If the limit of the ratio exists and is finite, then the original limit is the same:
lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7

Therefore, lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7.

[rkhitsharma]

34:00 mistake found
Answer is 5 and not 3/2.
If we reduce both equations we will get
x^5-1/x-1

= 5(1)^4

= 5 ans.
Same ans as in ncert

[jeevangoyal]

Ek question ka answer 108/7 correct tha toh aapne 162/7 nikala 😂😂😂😂😂

[mahijain]

Your teaching style is same as Ashu sir 😂