Finding Reverse of a Number | Java | Detailed Explanation

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[Anikets_Art_Gallery]

Extremely good explanation it became like crystal clear for

[wheresisgod]

beautiful explanation...better than other YouTubers! thanks much

[shanthinij]

Sir upload Java full concept video. It is very much useful for us.

[mithank]

Thank you so much, RESPECT from karnataka

[aarulmozhinandhini]

After a Long Gap u are back....thanks for the video bro🤩

[payalbhuyan]

thank god i watched ur video i understood the logic so well thank u so much

[ashishraj]

bro your explaination is great thank you so much🙏

[shivu]

Awesome bro.. how did you learn this deeper....Keep up this work....

[techbaap]

Awesome explanation brother. We need more videos from you.

[rajeshkanna]

But if user enter 100, we get output 1 and not as 001....how can we solve this?

[coctamizhan]

Soo... Palindrome number and reverse a given number are same?

[abhiram]

Bro please explain string programs also

[zhawu]

Class reverse {
Public static void main (string[]args){
Int n=1234, r;
While(n>0)
{
r=n%10;
System.out.print (r);
r=n/10;
}

}
}

[ravi]

public class Playground {

public static void main(String[] args) {
final var number = -102;




}

// Will not work for negative numbers
private static int reverse0(final int number) {
if (number >= 0 && number <= 9)
return number;

final int power = 10;
int input = number;
int reverse = 0;

while (input > 0) {
int lastDigit = input % 10;
reverse = reverse * power + lastDigit;
input /= 10;
}

return reverse;
}

private static int reverse1(final int number) {
if (number >= 0 && number <= 9)
return number;

final int power = 10;
final boolean isNegative = number < 0;
int input = isNegative ? number * -1 : number;
int reverse = 0;

while (input > 0) {
int lastDigit = input % 10;
reverse = reverse * power + lastDigit;
input /= 10;
}

return isNegative ? reverse * -1 : reverse;
}

private static int reverse2(final int number) {
if (number >= 0 && number <= 9)
return number;

final int power = 10;
int input = number;
int reverse = 0;

while (input != 0) {
int lastDigit = input % 10;
reverse = reverse * power + lastDigit;
input /= 10;
}

return reverse;
}

// Same as above but less lines
private static int reverse3(int number) {
if (number >= 0 && number <= 9)
return number;

int reverse = 0;
while (number != 0) {
int lastDigit = number % 10;
reverse = reverse * 10 + lastDigit;
number /= 10;
}
return reverse;
}
}

[ashishmj]

You need +Reverse to print the number right?

[manojkumar-ifxu]

please make a series in pattern printing program and one solution with explaination of this pattern
1 2 3 4 5
10 9 8 7 6
11 12 13 14 15
20 19 18 17 16

[rm.]

The above method of reversing a number won't work if the last digit os number is 0 .
e.g: 5430
Can you please tell me how to achieve that

[amanmahato]

Good
But it would be better if you've done it neatly.

[venkatvenkat]

Bro simple ah reverse for loop laye potrulame why this much explanation. For(int i=array.length-1;i>=0;i--){
}