AP Calculus BC Lesson 9.6

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Topics: Finding speed, initial position, distance traveled, velocity vectors, and acceleration vectors of parametric equations and vector-valued functions

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0:00 Motion Formulas
1:55 MCQ 1
3:08 MCQ 2
4:26 MCQ 3
6:19 MCQ 4
8:22 MCQ 5
10:07 MCQ 6
13:35 FRQ 1
18:27 FRQ 2
  1. Elizabeth Fein
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0:05 - Motion Formulas
1:55 - MCQ 1
3:08 - MCQ 2
4:26 - MCQ 3
6:19 - MCQ 4
8:22 - MCQ 5
10:07 - MCQ 6
13:35 - FRQ 1
18:27 - FRQ 2

elizabethfein
Автор

Hello! I had a question about one of the problems that you solve at the 16:31 mark. I'm confused as to why you treated finding the slope of the tangent line different than finding the derivative of a vector-valued function. For vector-valued functions, why do you take the derivative normally? But then with finding the slope of a tangent line we treat it differently through dividing the derivative of y over the derivative of x. Hope that made sense!

daliazidan