How to BALANCE any Chemical Equation - ABCD Method | Best Way to Balance Chemical Equation

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App.

LAKSHYA Batch(2020-21)

Registration Open!!!!

What will you get in the Lakshya Batch?

1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.

2)Live Classes and recorded Video Lectures (New, different from those on YouTube)

3)PDF Notes of each class.

4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.

5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.

6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)

7)In case you missed a live class, you can see its recording.

8)You can view the videos any number of times.

9)Each chapter will be discussed in detail with all concepts and numericals

10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.

****Test Series for XI & XII****

We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.

MoLE ConCepT in 40 mins : CBSE / ICSE : CHEMISTRY : Class 10, Class 11, Class 12
MOLE Concept in 6 mins : Class X CBSE / ICSE :
MOLE CoNcEpT : STOICHIOMETRY : Class X , XI , XII : CBSE /ICSE
MolecuLar FormuLa and EmperiCal Formula | Percentage CompositioN | Class 10 , 12 ICSE / CBSE
Mole ConcepT 01 | How To CalcuLate Number of Moles | Mass Volume Relationship | Revision
How to BALANCE any Chemical Equation - ABCD Method | Best Way to Balance Chemical Equation
Mole Concept || Class 9,10,11 || Stoichiometry || Percentage Composition | Compilation Of OLd Videos

[PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App.



LAKSHYA Batch(2020-21)

Registration Open!!!!

What will you get in the Lakshya Batch?

1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.

2)Live Classes and recorded Video Lectures (New, different from those on YouTube)

3)PDF Notes of each class.

4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.

5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.

6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)

7)In case you missed a live class, you can see its recording.

8)You can view the videos any number of times.

9)Each chapter will be discussed in detail with all concepts and numericals

10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.


****Test Series for XI & XII****

We provide you the best test series for Class XI, XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.

MoLE ConCepT in 40 mins : CBSE / ICSE : CHEMISTRY : Class 10, Class 11, Class 12
MOLE Concept in 6 mins : Class X CBSE / ICSE :
MOLE CoNcEpT : STOICHIOMETRY : Class X, XI, XII : CBSE /ICSE
MolecuLar FormuLa and EmperiCal Formula | Percentage CompositioN | Class 10, 12 ICSE / CBSE
Mole ConcepT 01 | How To CalcuLate Number of Moles | Mass Volume Relationship | Revision
How to BALANCE any Chemical Equation - ABCD Method | Best Way to Balance Chemical Equation
Mole Concept || Class 9, 10, 11 || Stoichiometry || Percentage Composition | Compilation Of OLd Videos

[anilkumartiwari]

The answers of first 2 equations are :
1. S + HNO3 -> H2SO4 + NO2 + H2O
Solution • S + 6HNO3 -> H2SO4 + 6NO2 + 2H2O
solved equation -> Sulphur : a = c..(1), Hydrogen : b = 2c + 2e..(2), Nitrogen : b = d..(3), oxygen : 3b = 4c + 2d + e..(4)
Let *b = 1
So, *d = 1
Now, from equation (2) and (4), we can write
(b = 2c + 2e) and (3b = 4c + 2d + e)
[1 = 2c + 2e] and [3(1) = 4c + 2 (1) + e]
[1 = 2c + 2e] and [3 -2 = 4c + e]
[1 = 2c + 2e] (5) and [1 = 4c + e] (6)
~ {2c + 2e = 4c + e}
~ {2c - 4c = -2e + e}
~ { -2c = -e }
~ { 2c = e } (substitution of e - class 10, chapter 3)
Again from equation 6
1 = 4c + e { where e = 2c}
4c + 2c = 1
6c = 1
*C = 1/6
And for e = 2c
e = 2 × 1/6
*e = 1/3
*a = c = 1/6
Now, after putting values, we will get
-S + 6HNO3 -> H2SO4 + 6NO2 + 2H2O
2. Cu + HNO3 -> Cu (NO3)2 + NO2 + H2O
solution • Cu + 4HNO3 -> Cu (NO3)2 + 2NO2 + 2H2O
- Copper : a = c..(1), Nitrogen : b = 2c + d..(2), Oxygen : 3b = 6c + 2d + e..(3), Hydrogen: b= 2e..(4)
So, let *b= 1
*e = 1/2 (4)
From equation (2)
b = 2c + d, we get
d = 1-2c (substitution of d - chapter 3 class 10)
So in equation 3, we can write
3b = 6c + 2d + e (where d = 1-2c, e = 1/2, b= 1)
3(1) = 6c + 2(1-2c) + 1/2
3 = 6c - 4c + 5/2 ( after calculation)
So, 2c + 5/2 = 3
*c = 1/4 [ this method is same as finding math's x😂]
* a = c = 1/4
Now, d = 1-2c
* d = 1/2 (after calculation)
Hence, after adding the value of a, b, c, d, e
We will get - Cu + 4HNO3 -> Cu (NO3)2 + 2NO2 + 2H2O
#substitution is nothing but writing something simmilar which will be equal to 2nd value for solving 2nd value
Like - 5 = b + c
So we will find smth with variable b and equal to c -
C = 2b
So we can make this equation - in single variable - 5 = b + 2b, such that we can find the answer

[IMS]

Sir has come as a saviour for people like me who find it difficult to balance equation.

[_bit_abhi]

Anyone who is watching this awesome lecture in 2023 🥲🥲

[shubhamchauhan]

Best teacher award goes to him....if agree hit like....

[cricketworld]

2 saal ka confusion 5 minute me khatam ho
Lord for a

[pranayverma]

Any one of 2020 boards hit like👊👊👊👍👍👍👍👍👍👍👍

[YuvrajSingh]

S + 6 HNO3 H2SO4 + 6 NO2 + 2 H2O
Cu + 4 HNO3 Cu ( NO3 ) 2 + 2 NO2 + 2 H2O
Sir, a very big thanks to you 🙏
Watching after almost 4 years and this trick was amazingly perfect like magic 👌👌

[shobhithyanki]

First, I thought what is this method 🙄?
But when I tried it ..
literally I just love this method
So easy and helpful

[jayanthvenavenka]

1st question's answer: S+6HNO3 ---> H2SO4+6NO2+2H2O
2nd question's answer: Cu+4HNO3 ---> Cu(NO3)2+2NO2+2H2O

[shahedulalamshahed]

Legends don't come in a day or night .Legends come by their hard working.Salute you sir💕❤💕.

[wntflum]

Sir you made this lecture 6years ago but today it is useful for me...Thanks alot sir

[arubasultan]

I can't even describe how thankful I am to you, , , this was so much necessary for me. I was always confused with hit and trial. Now I have something logical and easy just because of you, thank you so much sir!!! 🥰

[adityarajparichha]

Thank You Very Much Sir 😊
H.W. Question Answer -
1) S + 6HNO₃ —> H₂SO₄ + 6NO₂ + 2H₂O
2) Cu + 4HNO₃ —> Cu(No₃)₂ + 2No₂ + 2H₂O

[fatimaanwaar]

Sir I am also a chemistry lecturer but seriously I didn't know about this trick but this trick helped me a lot. I used this trick to balance the equation in the classroom and the whole class room applauded me a lot just because of you...🤩

[karanpreetsingh]

Yes sir, it's really work!
1 equation:-
Let:- b=1 ;
After doing calculation:-
d=1, c=1/6, a= 1/6, e= 1/3 comes.
The answer:- S+6HNO3---->H2SO4+6NO2+2H2O
A'm correct or not?

[vivekvirat]

Alakh sir is best teacher in India
Sahi baat hai toh like karo. Plase

[fsamarthdeshlahre]

a = 1 b=6 c=1 d=6 e=2 we know that b = 2× 1 + e putting the value in 3b = 4c+2d +e also b = d there for we get e =2 putting e =2 in solution b =2c+2e we get b =6 and we know that b = d s d =6 and the equation formed is S + 6HNO3 => H2SO4 +6HNO2 + 2H2O this the correct solution for balancing it

[ujjwal]

Hw Ist equation answers
question
S + HNO3 TO give H2SO4 + NO2 + H2O
Answer
S + 6HNO3 + 6NO2 + 2H2O
Message: Thx for the homework it is easy i got b=d so i let c=1 and there is a equation in which 3 three variable are there b, d, e, i also got b=d, a=cand in the other equation there I got 2 variable after putting c=1 then in the equation where 3 variable exist I put b=d in RHS side where equation in which is put b=d is 3b=4+2d+e after putting b=d on rhs I got 3b=4+2b+e now just subract 2b from 3b then we have two equation Ist b=2+2end b=4+e multiply 2nd by 2 then eliminate e now you have your all the values

[devendrapratapsingh]

Sir pahle b=1 lege to d=1ho jayega aur phir hydrogen wale aur oxygen wale me elimination method laga denge isse e=1/3aayega aur c=1/6 and a=1/6 aur phir put karne ke baad multiply by 6 to equation balanced ho jaayegi