16. Advance Illustration | Capacitance | Analyzing Capacitive Circuit-4 | by Ashish Arora

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[saketmaurya]

for those solving by taking potential on -ve terminal of 10V as x on other side x+10 and taking 0 on -ve terminal of 20V

you will get x = 150/12

q = cv

and q(6uf) = 6(150/12 - 20) = -45uc

[MominParveez]

with due respect sir,
in these cases while distributing potential how can we identify which plate is +ve or other way ?? i mean it depends while writing equation for node...
thank you

[varunkhatri]

sir plze tell me how there is a node at x?

[SandeepChauhan-dpqf]

Sir advance illustration is enough for jee advance

[goofyvlogs]

If I m assuming X+20 and X, my answer is coming 195
Why???

[iota]

mistake : thought after infinite time 6uF capacitor will act as open circuit

[aadityasharma]

Sir I have taken another node as x so I am getting -ve 45....Is that wright...???

[AnkitRaj-yktv]

what would happen if we take zero potential at -ve terminal of 20 V battery ?

[yuvrajcharan]

sir how you are distributing potential like in previous Q you hve written x+20 and in this Q you have written x-20 this make me confuse

[PrashantSingh-tpgj]

Sir,
I took potential to be 20v, (x)v, (x+10)v, 0v where you took (x)v, 0v, 10v, (x-20)v.
But I didn't get my answer.please clearify