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Prove that Q10. Cot inverse (√1+Sinx + √1-Sinx)/(√1+Sinx - √1-Sinx) = x/2 || miscellaneous ch2 12th
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#trigonometry #12thmaths #inverse_trigonometric_function
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#trigonometry #12thmaths #inverse_trigonometric_function
thanks watch this video
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Seekho aur sikhao
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cot inverse {root (1 sin x) root (1-sin x) upon root (1 sin x) - root(1-sin x)} is pi/2
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Prove that Cot inverse (√1 Sinx √1-Sinx)/(√1 Sinx - √1-Sinx) = x/2
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cot^-1[sqrt(1 sinx) sqrt(1-sinx)]/[sqrt(1-sinx)-sqrt(1-sinx)] =x/2
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Prove that: `cot^(-1){(sqrt(1 sinx) sqrt(1-sinx))/(sqrt(1 sinx)-sqrt(1-sinx))}=pi/2-x/2
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cot^-1(√1 sinx √1-sinx/√1 sinx-√1-sinx)