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Integral 0 to pi/2[ log(sinx) - log(2 cosx)]
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Integral 0 to pi /2[ log(sinx) - log(2 cosx)]
plus two definite integral 2023 board exam question
plus two definite integral 2023 board exam question
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Evaluate the integral 0 to pi /2 log(sin x) dx
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Integral 0 to pi/2[ log(sinx) - log(2 cosx)]
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`int_(0)^(pi2)log(sinx)dx=` | Class 12 Maths | Doubtnut
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Prove that `int_(0)^(pi//2)log (sinx)dx=int_(0)^(pi//2) log (cosx)dx=-(pi)/(2) log 2`.
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Integration of log sin x between 0 and pie/2.
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`int_0 ^(pi/2) log sinx dx = int_0 ^(pi/2) log cosx dx = 1/2 (pi) log(1/2)`
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integration 0 to pi/2 2log sinx - log sin2x
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Evaluate the integral from limit 0 to π/2 log sinx dx
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`int_(0)^(pi//2)log(sinx)dx=` | Class 12 Maths | Doubtnut
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0 TO PI/2 LOG SIN X DX OR 0 TO PI/2 LOG COS X DX
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