Brain Teaser Challenge: Can You Crack The Code?

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Tricky riddle to check your intelligence.
A room is locked with a 9-digit passcode. The passcode is a very special number with each of the digits from 1 to 9 appearing once.
The complete passcode is a 9-digit number and it is evenly divisible by the number 9.
So when you divide this number by 9, you wont get any fractional value.
When you remove the last digit (or the rightmost digit), you get an 8-digit number.. this number is evenly divisble by 8.
When you remove one more digit from right, you get a 7-digit number... which is divisible by 7.
This property continues all the way down to one digit.
Can you find the actual 9-digit passcode to get through the door.

It's a billiantly composed puzzle...defintely not an easy one to crack... and I bet you'll find this problem very interesting to solve. I encourage you to solve this riddle by yourself.

You can share puzzles and riddles with me on these links:

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One more logic we can use to make it even simpler. We can easily reach at below two possibilities:

_ 4 _ 2 5 8 _ 6 _
_ 8 _ 6 5 4 _ 2 _

Now, as first 3 digits are divisible by 3, and middle 3 digits are also be divisible by 3 (to make first 6 digits divisible by 6), last 3 digits will have to be divisible by 3 also. That funnels down to only 4 possibilities which can be reduced to 2 by checking divisibility from 8. Now check these 2 numbers for divisibility of 7 and you are done.

wholesomeparas
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Your videos are normally good, but this was on another level. Really enjoyed this.

justanotherviewer
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This is the first video of yours I have seen, and it was excellent fella! Brilliant work right there! I have subbed! 💯👍🙏

richardabkstorm
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It took me 3 hours to solve this. It made my day🤗.

puhazhmathimohan
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7:50 instead dividing by 7. We can use divisibilty of 8-number formed by last 3 digit must be divisible by 8

rkghosh
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Excellent work....your way of explanation was easy and fantastic

subhrajitbanikroy
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I solved it exactly same but was stuck at divisibility rule of 7, so saw your solution and felt relaxed 🤘😇❤️

manshulgarg
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I felt so guilty and dirty checking all possibilities for 7 that it's quite relieving to know it was the only way to go about it.

jacoboribilik
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Whenever8 I feel low or disturbed.. I search for something engaging. Especially I love mathematical riddles. This is good one. I solved it in 5mins

rameshkiran
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I wonder how to writre a program that'll crack it using divisibility rule.

TheJackal
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This is awesome. And magic of mathematics

naimeshpatel
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We can change the order of the steps at 4:00.
As F is 4 or 8 and FGH is divided by 8, GH is divided by 8. As G is an odd number which is not 5, GH = 16, 32 or 72.
As G + H + I is divided by 3, if GH = 16, I should be 2, 5 or 8. But none of them satisfies that I is an odd number and is not 5. So GH = 32 or 72.
It gives H = 2 and C = 6, and G = 3 or 7.
As D + E + F is divided by 3, F = 4, so B = 8
Again, G = 3 or 7. When G = 3, H = 1 (then {A, C} = {7, 9}) or 7 (then {A, C} = {1, 9}). When G = 7, H = 3 (then {A, C} = {1, 9}) or 9 (then {A, C} = {1, 3}). So we get 8 numbers, so we have only to divide ABCDEFG of those 8 numbers by 7.

SuperPassek
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Alhamdulillah... I solved it by a different method which is more easier. 😊

tanzeelasiddique
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Took me 30 minutes to solve this ... First arrived at the conclusion 183654729 ... Skipped to the end of the video and saw that the first and third digit were interchanged and realized my numerical fault.Counting it as solving though ... As usual great puzzle.

_rajatchakraborty
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Kinda happy to say that up until [2:27] or so I deduced myself. I cracked it but I did so with an excel sheet, starting with 5 in the middle, then the 1st digit, then worked my way up, deleting inconsistencies.
Obviously took me far longer but yes! - I solved it and reached the same result.

It won't save me from a ticking bomb but hey at least I wouldn't starve in the room. :)

p.zansei
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BEST CHANNEL FOR SHARPING THE RUST OF BRAIN

Poojasharma
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From many answer one is... 123, 252, 561
It took me 10 mins bt i did it

faizalshaikh
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Good puzzle. You can make it more complicated by saying the digits are 0-9; instead of 1-9; and ‘0’ cannot be used as the left most digit. Now readers have to first select 9 digits from 10 digits. There is a solution with ‘0’ as well😎. Try it,

rsc
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My first few steps are also the same but I used divisibility rule of 8 instead of using "that if a number is divisible by 8 then it must be divisible by 4 and 2" which gives me 5 possible combinations (472, 496, 672, 872, 896)

VB
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I got the secret code answer as 987, 654, 123.

nadarjustin