Distributive Law for Sets A u (B n C) = (A u B) n (A u C) Set Theory Proof

Distributive Law for Sets A u (B n C) = (A u B) n (A u C) Set Theory Proof

[ilovelamp]

Hey man I love your content. You have helped me out with so much over the years. Cheers!

[quandingle]

Dude wth It became very easy after learning from u

[ai-Able]

Wouldn’t it be more rigorous showing both sets are subsets of each other to confirm the equality?

[anymorendlovu]

Thank you for your video I got the idea now, but I tried to prove A u (A^ n B) = A u B and got stuck on the complement part

[zaylo]

When I see this video, I was like so fast and it blew off my mind XD That is some nice rocking teaching XD Nice costume XD So damn easy to understand XD

[boushrahaidar]

Cannot we multiply A union with B intersect C as another method?

[oneaboveall]

can u do that question with it's venn diagram

[aetheriumzer]

Under what definition. theorem, or law supports the step in 2:14 ?

[shadabdulsamad]

Can you prove it from right hand side ?

[shadowx]

If A = {1, 2, 3), B = {4, 5, 6), C = {7, 8, 9).
then verify that :
) AU (Bn C) = (A U B)nA Uc)
1) A n (B U C) = (A n B) U (A n C)