Statics of Rigid Bodies Chapter 2 Couples Introduction (PH)

Part I Statics of Rigid Bodies
Chapter 2 #Couples #Moment

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[edmarebido]

Focus on the downard forces:
∑Fv = 0 (upward positive)
∑Fv = –60 + (–20)
∑Fv = –80 (downward forces)

∑Ma = 0 (clockwise is positive)
∑Ma = 60(3+1) + 20(1+1.5)
∑Ma = 290 kN×m

We know that...
Ma = Fv(d)
therefore...
290 = 80(d)
d = 290/80
d = 3.625 m

Now, focus on the upward forces:
∑Fv = (upward positive)
∑Fv = 50 + 30
∑Fv = 80

∑Ma = 0 (clockwise positive)
∑Ma = –50(1) + (–30(6))
∑Ma = –230 kN×m

Ma = Fv(d)
230 = 80(d)
d = 230/80
d = 2.875

[reymartgaan]

50(1)+30(6)=230 ; 50KN + 30KN = 80KN

230=80(d)
d=2.875m

20(1.5+1) + 60(4)=290 ; 60KN + 20KN = 80KN

290=80(d)
d=3.625

[mia-gzmj]

Thankyou sa CE BOX, u r a life saver. Sana po may reactions. Hehe

[arknghel]

Sir ang galing n'yo po magturo. I'll recommend your channel to all of my classmates.

[josephdelrosario]

Galing niyo po mag explain. Parehas po kayo ni ma'am Domingo sa PHINMA University of Pangasinan. Parang may similarities po kasi kayo sa way ng pagtuturo hehe

[sportzquiz]

Sir saan galing yung 2.875 at 3.625 sana mapansin po thank you

[ayumiwynx]

Good evening po. Bakit po ung sa Mc -15 ung nakuha kong sagot. Di ko mapalabas na 60

[darylcala]

Sir yung 2.875 at 3.625 . Paano yun kukuhanin sir or assumption lang sya ba sya? Hehhe confused ako jan na part.

[samsunggalaxyyyyyy]

Can you explain how did you get the distance between the forces (2.875 and 3.625) or anyone here can explain

[rindokidokidok]

sa pagkuha po nung distance po ba aykinuha muna yung resultant of upward and downward forces seperately then kinuha po yung moment po nila seperately den tas po sinubstitute po sa M=R(d) seperately para po makuha yung distance nila seperately tapos po ay pinagminus po yung d(downward)-d(upward) para makuha po yung d ganto po kasi ginawa ko :)

[tonibautista]

hello po ung paglagay po ba nang 80 kn ay kahit saan o may required na position depende sa nakuha mo

[gianaizeljavier]

Hello po, may lumang notes po ako dito sakin sa d sa couple. Di ko lang po sure kung pwede. Eto po:

(M1/F1 + M2/F2)/2

Pwede po ba to?

[johnrexsalcedo]

Sir dba Po Yung couples are two parallel forces that has the same magnitude but different in directions..bakit Po iba iba Ang magnitude Ng forces Ng couples NYU Po sir??

[bernadettebiason]

hello po. saan po kayo kumukuha ng sample problems niyo for your videos? salamat po.

[jasminewatsons]

sir kung couples ba siya, disregarded ba yung equation ng moment na €M=Rd ?

[artanthonyantonio]

hi sir. been watching your video everytime. may sample problems po ba for forces on space. thanks🙂

[minecraftengineer]

Hi sir ! Sa videos niyo nalang po ako nag de-depend kasi hindi kami tinuturuan ng prof namin. Maraming salamat po !

[shakssy]

Bakit po sa Moment of A nag -50(1) po kahit upward ang force?

[geraldfernandez]

Sir tanong ko lang po, sa may book po kasi na ginagamit ko, pag counterclockwise-positive, pag clockwise naman-negative. Na confuuse po akoooo :((

[normangaming]

Sir sana po may exercises po kayong pinopost every after topic hehehe. salamat po❤