[2221–7106] - (Question 5) - IB Math AA HL MAY 2021 TZ1 - Explanation

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5. [Maximum mark: 8]
(a) Show that sin2x + cos2x - 1 = 2sinx (cos x - sinx). [2]
(b) Hence or otherwise, solve sin2x + cos2x - 1 + cos x - sinx = 0 for 0 x 2π. [6]
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