LeetCode Daily: Longest Subarray With Maximum Bitwise AND Solution in Java | September 14, 2024

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🔍 LeetCode Problem of the Day: 2419. Longest Subarray With Maximum Bitwise AND

In today's LeetCode daily challenge, we solve the Longest Subarray With Maximum Bitwise AND problem by identifying the longest subarray where all elements are equal to the maximum value in the given array. The solution is implemented in Java.

👉 Solution: Pinned in the comments.

🌟 Problem Description:
Given an array of integers, the task is to find the longest subarray where all elements have the maximum bitwise AND value from the entire array.

🔑 Key Points:
Max Value Identification: First, identify the maximum value in the array.
Longest Subarray: Traverse the array to find the longest contiguous subarray where each element equals this maximum value.
Efficiency: The solution runs in linear time, O(n), by scanning the array twice.

📝 Code Explanation:
Step 1: Iterate through the array to find the maximum value.
Step 2: Traverse the array again to calculate the longest subarray where the elements match the maximum value.
Optimization: The length of the longest contiguous subarray is updated whenever we encounter the maximum value.

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class Solution {
public int longestSubarray(int[] nums) {
// Step 1: Find the maximum value in the array
int maxVal = 0;
for (int num : nums) {
maxVal = Math.max(maxVal, num);
}

// Step 2: Find the longest subarray with elements equal to maxVal
int maxLength = 0;
int currentLength = 0;

for (int num : nums) {
if (num == maxVal) {
currentLength++; // Extend the current subarray
maxLength = Math.max(maxLength, currentLength);
} else {
currentLength = 0; // Reset the length when the value changes
}
}

return maxLength;
}
}

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