Every Finite Integral Domain is a Field Proof

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Every Finite Integral Domain is a Field Proof
  1. The Math Sorcerer
  2. Field
  3. Abstract Algebra (Field Of Study)
  4. proof
  5. Mathematics (Field Of Study)
  6. mathematical proof
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Комментарии
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Modern algebra is my weakest maths branch; this made a lot of sense. Thanks for the video!

kevinstraka
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How do we know that R contains 1? We only know that R is an integral domain, which means multiplicative identity is not guaranteed.

MellowJK
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This was really helpful. Thanks a bundle.

mehmoodkhan
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I love abstract algebra. I am in 11th grade (soon 12th grade) and I am self-studying it.

viktorramstrom
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Which book you are using, i am using Joseph gallien 7th edition

depressedguy
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This is an assignment question for me. I just can't get my head around rings yet. If I have to watch a video, rather than proving it myself, then I think I'm still learning. Do you agree?

jasonthomas
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Thank you sir for the video it was very helpful and easy to understand

swezaldias
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I've found this problem on Herstein 3rd. he define integral domain as commutative group with no zero divisor, but he doesn't mention that integral domain should have 1. and i got stuck, how to prove existence of 1 in integral domain? or is it just by definition?

linggamusroji
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