Leetcode Question 172 'Factorial Trailing Zeroes' in Python

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Given an integer n, return the number of trailing zeroes in n!.

Note that n! = n * (n - 1) * (n - 2) * ... * 3 * 2 * 1.



Example 1:

Input: n = 3
Output: 0
Explanation: 3! = 6, no trailing zero.
Example 2:

Input: n = 5
Output: 1
Explanation: 5! = 120, one trailing zero.
Example 3:

Input: n = 0
Output: 0
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