(Cosec-Cot)2=1-Cos/1+Cos | Show That (Cosec Theta-Cot Theta)^(2)=(1-Cos Theta)/(1+Cos Theta)

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Prove The Following Trigonometric Identities Where The Angles Involved Are Acute Angles For Which The Expression Are Defined | AK MtCourse | by Anand Kushwaha

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(cosec-cot)2=1-cos/1+cos

(cosec-cot)²=1-cos/1+cos

(cosec theta-cot theta)2=1-cos theta/1+cos theta

(cosec theta-cot theta)²=1-cos theta/1+cos theta

(if) (cosec theta-cot theta)^(2)=(1-cos theta)/(1+cos theta)
(cosec theta-cot theta)^(2)=(1-cos theta)/(1+cos theta)

cosec theta minus cot theta ka whole square equal to 1 minus cos theta by 1 + cos theta

cosec theta minus cot theta ka whole square equal to

cosec theta minus cot theta ka whole square

cosec theta minus cot theta ka whole square barabar 1 - cos theta by 1 + cos theta

cosec theta minus cot theta ka whole square barabar 1 - cos theta by 1 + cos theta

cosec theta minus cot theta ka whole square barabar

cosec theta minus cot theta ka whole square barabar what

show that (cosec theta-cot theta)^(2)=(1-cos theta)/(1+cos theta)

(Cosec-Cot)2=1-Cos/1+Cos | Show That (Cosec Theta-Cot Theta)^(2)=(1-Cos Theta)/(1+Cos Theta)
  1. AK MtCourse
  2. AK MtCourse
  3. (cosec-cot)2=1-cos/1 cos
  4. (cosec theta-cot theta)2=1-cos theta/1 cos theta
  5. (if) (cosec theta-cot theta)^(2)=(1-cos theta)/(1 cos theta)
  6. (cosec theta-cot theta)^(2)=(1-cos theta)/(1 cos theta)
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