Types 1,2&3 numerical from Horizontal Curve | 5th Sem | Prashant YT | CTEVT |

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T.D=346.41m
L.C=628.31m
P.C=1710.03m
P.T=2338.34m
L.L.C=600m

DipMonOfficial
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Tangent distance =346.41m
Length of curve=628.31m
Chainage of PC= 1710.03m
Chainage of PT=2338.34m
Length of long chord =600m

kabitagiri
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For Types one..
TD = 346.410 m
LC= 628.318 m
PC = 1710.03 m
TP= 2338.348 m
LC= 600 m
FROM CHITWAN

kumarrajiblovely
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Interesting xa hau survey 5th haldinu pareyo sabai daju

JerseyNo.
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Kahile sama ayuxa hola sir type 4 ko numerical

dambarmukhiya
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Types 4 numerical needed but exam is held tomorrow

XSlayerYt
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Dai Astai sab subject ko
Yo video jastai garaunu na

Rajeshsah-umkf