AC Thevenin's Theorem (Full Lecture)

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In this lesson we'll learn to simplify a complicated series-parallel AC circuit into its Thevenin's equivalent consisting of a Thevenin's equivalent voltage source in series with a Thevenin's equivalent impedance in series with a variable load impedance. Ideally the variable load will be unaware of the substitution, however, the Thevenin's equivalent circuit will be notably easier to build and solve for desired circuit properties. (Full Lecture)

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What I find surprising about this is the way the model remains accurate even when Zload impedance is lower than the full open assumption used to get the numbers. When Zload declines and current through that arm increases, the increase in voltage drop across Z1 and Z3 in series must exactly balance the declining shunt of current (and declining voltage drop) across the parallel Z2. Presumably that would come out with a rigorous proof....

spelunkerd

Hi Jim Absolutely brilliant many thanks, think's for the link all the very best Rob

robingadney

how did you get -390i ohms for the capacitor's impedance at 4:14? Your formula gives a magnitude of .00256353

Kimchi_TV_

Please sir can you do something on magnetic circuits. Theirs no-one with an understandable accent doing it on youtube.

ashlynnundlall

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