Mechanics of Materials: Exam 1 Review Problem 3, Material Properties

Top 15 Items Every Engineering Student Should Have!

This video is NOT sponsored. Some product links are affiliate links which mean if you buy something we'll receive a small commission.

Please consider supporting the channel by subscribing, commenting, and liking each video. This moves these videos up the search list and helps me greatly. Thank you for watching.

This video is copyrighted by the Jeff Hanson for the private use of our audience. Any other use of this video or any pictures, descriptions, or accounts of the video without written consent from Jeff Hanson is strictly prohibited.

[nourdarwish]

Thank you Dr.Jeff. For part (b), I guess you forgot to multiply by the factor of safety that equals to 1.3, so the correct answer should be found as follows:

Stress_yield= 26 ksi
Stress_max = Stress_y/ F.S
Stress_max = 26/ 1.3
Stress_max= 20 ksi

S_max= F/A
F_max = 20 *(pi/4 * 2²)
F_max=62.832 kips✔️

[janoycresva]

For part b, wouldn’t it be 62.83 kip because you were also asked to add a Factor of Safety of 1.3?

[manuboker]

Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))

[alexradu]

For part D, isn't modulus of resilience the area under the triangle part of the graph before it gets to deformation? SO the volume would be equal to energy divided by area under the linear part of the graph?

[fathinataboaba]

Shouldn't it also be 962 instead of 96.2 since we are multiplying by 1000? For 9000 it was 9 x 1000 so it should be 26 x 1000 x 0.037 = 962