Simplifying | calculator is not allowed #maths

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Problems when a calculator is allowed: 1+1
Problems when calculators isn’t:
Edit: can y’all stop replying to this. This is a fucking joke and y’all taking this shit seriously

clayed
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"How do you celebrate new years?"
"Well it's complicated"

Random_OnlyChannel
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Salesman learning calculus 2 for the 4th time with this one 🗣️🗣️🔥🔥🔥🔥

vikramrawat
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Solution :
Given, n = 2025

First of all (n-1).(n+1) = n^2 - 1
Now (n^2 - 1). n = n^3 - n

Now simplify,

n^3 - n + n = n^3
Now cube root of n^3 will be n
So the answer is n which is 2025

NeverImagined
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❤ Thank you
This made me laugh with joy and happiness

GurmaniMusafir-mb
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My approach was:
- Taking 2025 common, substituting 2024 and 2026 with (2025-1) and (2025+1)
Simplifies to-
[2025{2025.2025 - 1.1 + 1}]^(1/3)
[2025.2025.2025]^(1/3)
'.' represents multiplication operator

AarushJEE-vk
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Manim is now globally used
Thanks to 3b1b for introducing Manim which made all of our understanding better in math

shobharaniheddula
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It looks confusing at first, but the second time it becomes simple

lcleflo
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Let x= 2024
2025= x+1
2026= x+2
Put the values you will get (x+1) ^3
Hence taking cube root = x+1 = 2025(Ans)

borntolearn
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He just made math a whole a lot easier in the future for me since I’m in 6th grade

Mickn
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For all the people saying what’s the point, I can just use a calculator. This question isn’t testing your arithmetic skills. It’s testing your problem solving skills, and how you can take this problem and simplify it. It’s an incredibly useful skill not just in other areas of mathematics, like proving things in real analysis, but also life.

sammurphy
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I love this one
It matches with the beat

RoomsLowDetailed
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Take x = 2025
2026=x+1 and 2024=x-1
Take x common, expression becomes [(x-1)(x+1)+1]*x = (x^2-1+1)x = x^3, so cube root of x^3 = x = 2025

gauranshvarshney
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well we know that n(n+1)(n+2)+(n+1)+(n+1) is how the expression inside the cube root would be written
multiply out n(n+2), giving you (n^2 + 2n)
so you have (n+1)(n^2 + 2n)+(n+1)
factoring out (n+1), we get, (n+1)(n^2 + 2n +1)
we know that (n+1)^2=n^2 +2n+1
so it can be written as (n+1)(n+1)^2
or, (n+1)^3
since theres a cube root, the cube and root cancel(i know that the cube root of anything yields 3 values but the other two are imaginary, which is why we're sticking with the principal value)
so the final product is n+1, which in this case is 2025
the explanation might make you think this is a long process, but doing it in your head is split second processes

Brid
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Salesman solving 10 grade questions with this one 🗣🔥🔥

ayaanfaisal-gcqk
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When the salesman starts doing math in front of the beggars instead of giving scratch tickets:

FederalBureauOflnvestication
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Easy just write 2024 as 2025-1, 2026 as 2025+1 and solve it's answer is 2025

rishavjain
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time traveller: what is the year now?

bro:

Enderbeastofficial
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kinda goofy seeing variables on youtube, i don't see them much here
though ty for the vid

Baconguy.alight
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This was actually a question on UKMT Intermediate Challenge 2025! I remember just doing it using the numbers instead of substituting them for n, though.

Coin-xw
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