116N. Small-signal model, MOS vs. BJT, input and output resistance, capacitance, cut-off

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Analog Circuit Design (New 2019)
Professor Ali Hajimiri
California Institute of Technology (Caltech)

© Copyright, Ali Hajimiri
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Epic level teaching Sir, i just feel privileged for getting access to these super informative lectures

prabhu
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Thank you alot for putting these high quality lectures for knowledge hungry students all over the world prof.Hajimiri! I've been following the lecture series and they have been excellent. I just wanted to stop by and tell you to please keep posting those videos for free, they're very educational. Thank you!

mertianyiva
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Very nice content (especially about the T model), and motivated teacher! Kudos from Belgium!

dasilvaleandro
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Thanks for sharing these videos :)
Just wanted to share that based on my simulations in real PDK’s, Ic of BJTs does NOT go to zero when Vce->0. Most reference books state that it does, but I’ve not been able to reproduce that result in any SiGe/CMOS PDK.

pbass
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28:07 Resistor aka a current source whose current is proportional to its own voltage.

Could have never thought about it that way

anuragjuyal
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legends quotes " What is the name of of the current source whose current is proportional to its own voltage it's called a resistor " Ali Hajimri

zinhaboussi
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Since W and L are small quantities, can we ignore Cox term in the Frequency relationship? Shouldn’t the denominator be always having the 1+2/3WL term and the frequency scaling a weak function of L?

krisjk
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Why don't we use the non-linear gate capacitance as a symbol in a large signal-model version of the MOSFET like how we use the base-emitter PN junction in the large signal model of the BJT? I guess that it would be a little misleading as the Gate capacitance is across the whole channel, and not just the gate to source. I'm just curious if there is an accepted notation for expressing the large-signal model of the MOSFET similar to the Ebers-Moll model of the BJT?

corydiehl
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The voltage across the channel is not uniform so why is the channel charge divided by Vgs - Vth?

mahamedducale
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someone can explain 50:28 to get ft plEASE

israelaruzamen