Static Variable Is Thread Safe OR Not

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In this video we will see the live example that how static variables are not thread safe.

#programming #cppprogramming #cprogramming

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You are doing a great job! To solve this particular issue, it seems like the easiest solution is to use an atomic library and define the variable "s" as atomic. This way, the mutex is no longer necessary. Thank you and good luck!

markusbuchholz

@CppNuts, please make a video explaining the concept of Semaphores in C++! You are the best explaining difficult concepts!

japusinbibe

That's why strtok_r should be used in favor of strtok for multithreaded code. strtok has a static variable. This is just an example, there are more functions which are not thread-safe.

ArjanvanVught

map<int, int> m;
m[1]=1;
m[2]=2;
m[3]=3;

m.erase(m.end());

for(auto ele : m){
cout<< ele.first<<" " <<ele.second<<endl;

}
Output is
1 1
3 3

But when i do
m.erase(--m.end());

Output is
1 1
2 2

Can you plz varify and tell me whats happening here

sachinkiragi

@CppNuts, at time 5:32, if thread1 is suspended right after m.unlock(), and thread2 increments s for some time, then doesn't thread1 print s as
I mean it is not guaranteed to print by thread1.

Can you please correct me if I'm wrong ?

ChaduvukondiFirst-lgvt

how to increase our cpp skills?? currently working only on c programming. want to switch to cpp position. Please share your thoughts.

sharathkumar

hey cpp nuts you didn't do video on vptr and vtable.

sharathkumar

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