Physics 15 Torque (21 of 25) More Examples: 3 T=? of Cable of Step Ladder

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In this video I will find the tension of a cable of a step-ladder with a 70kg person ¾ up the ladder.

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when you find torque C;so why didnt you subtract Force A on that equation? I really hope you will answer my question🙏🙏🙏

tsoojbaterdeneharvard
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@michel van biezen you said the tension is an internal force so was excluded when taking moments about pivot A but then why did you take it into account when taking moments about pivot C?

umairkhan-sism
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Mr. Michel, I believe you should habe drawn an accurate and self-explanatory free body diagram. Morever, why did you even take into consideration the right side of the ladder only while the tension also exists from the left side?

andrewjustin
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Hi Prof., may I ask

@minute 8:01, won't we need to take the sin(75.52°) of the upper triangle's 2M (hypotenuse) to get its vertical distance that is then perpendicular to tension "T"?

Nevertheless your video are extremely helpful, some of your examples I originally don't even know where to start.

Thank you

aywgus
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I encountered a similar problem to this. And it asks me to find the magnitude of the force exerted of the right side of the ladder on the left side. Is it the same with the tension acquired in this problem?

doz
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when you find the torque at C, why did you not include F in a and the mass mg? thank you

adamspaulsoriano
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These calculations of torque performed in plane XOY or in two dimensions. Is the calculation need to be performed in third dimension, plane ZOY, in order to can save someone who use it?

hasanyahya
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Can you please give us some more example of tension force like this one as when we take the right side for point c, that part is quite confusing for some of us, that would very helpful to understand how it works, thanks

m_t_jawaad
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Does hinge force exist at the c point ? and Is it considered an internal force ?

jaingfenglu
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Can I ask why the tension is not incorporated when taking the torque with respect to (A)?

hamadalqubaisi
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Hi why is the person not experiencing a normal force as he/she is standing on one of the steps of the ladder?

josephjoe
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please note something is wrong in this problem.... since when we consider only the right portion of the ladder and sum forces in the X-direction they won't add up to zero which means that the ladder is moving along X-direction in the horizontal i guess the solution is that the reactions at A and B must be along the direction of the members AC and BC respectively and thus we will obtain equilibrium along X and the answer for T will change it would be 218.75kg*m/sec2 or simply 21.875 please note since we're putting our content to the public we must provide correct solutions otherwise we'll teach some wrong concepts

amrsleiman
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In calculating the torque at point A, why didn't you include the tension?

maxellmilay
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I assume that if we used the LEFT side of the ladder to find the TENSION, "T", then we would arrive at the same I'll have to try that.. :) ....

ptyptypty
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what if we friction coefficient is not equal to 0?

mohitforimprovement
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If we take torque about B then tension will create an anticlockwise torque then which other force on BC ladder will create clockwise torque

chpopr
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I'm doing a project for uni of this same type of problem, the same type of ladder, but I'm trying to incorporate the effects of friction at the feet and I'm really stuck, I can't find any information on how to deal with this problem. Do you have any idea where I can get more information on this? Any info I find is just about a simple ladder leaning against a wall.

wildawhale
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So, does it mean tension at both sides of the rope are equal?

coal
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Why do we ignore torque = rFsin(theta) and simply use t = rF ?

gabe
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Would the tension on the left side equal the tension on the right side? Intuitively I want to say it must but when I calculate the tension I find it to be 221N on the left

hattrick