Limit with floor

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Here I evaluate a neat calculus limit with the floor function, namely the limit as x goes to 0 from the right of x to the floor of 1/x. It's a nice application of the definition of floor, and a quick and tasty math snack. This problem can be found in chapter 2 of Stewart's calculus textbook.

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Wait wasn’t that obvious?



Wait wait, it WAS obvious bc it only took you 2 minutes.



Try one minute next time yea? My attention will thank you.

blackpenredpen
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The solution was way easier than the limit looked! Really neat

GnarGnaw
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Thank you Dr. Peyam, this was fun! I enjoy watching you mix math disciplines together

Roarshark
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Good solution. You can generalize this result.

If a(n) is a positive valued sequence converging to 0, and b(n) is a sequence going to infinity, then a(n)^b(n) will go to 0.
The proof is straightforward. Let d be a number in (0, 1). There is a natural number n such that 0 < a(n) < d for n >= N. Assume wolog that b(n) > 0 for n >= N. Then

0 < a(n)^b(n) < d^b(n) for n >= N.

Now just apply the squeeze theorem and you’re done.

seanfraser
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I like the limit and I like the shirt Dr. Peyam. :)

bertrandspuzzle
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I used lim exp- (floor(1/x)*ln(1/x)) where x go to 0+. It's the same as lim exp(- floor(y) *ln y) where y go till infinity

tgx
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Your videos are so amazing! You're one of the people who inspired me to make a channel!

readabook
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Dr Peyam: *Solves the Riemann Hypothesis in two minutes*
Also Dr Peyam: *If you wanna see more Math videos, please make sure to subscribe to my channel*
Riemann: *Subscribes to Dr P*
Me: *Wow, this guy knows how to evaluate this hard limit*

frozenmoon
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x^[1/x]=exp([1/x]*ln(x)). It obviously goes to exp(+inf*(-inf))=0

ІгорСапунов
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I am sure the reasoning is correct! (Although the result is).

nournote
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Great trick would have never through of that

excessreactant
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Squeeze theorem isn't only valid for l<=f(x)<=l? I think I'm a little confused, doesn't 0<f<=0 leads to a contradiction? You know, because 0<0 implies 0 != 0. I may be missing something.

suscriptor
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Here's an interesting limit :
The same function in this video but the limit x tends to half (1/2)

adithyan
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I thought the floor function had brackets that were L and backwards L shaped. Can I just use square brackets?

ZipplyZane
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Nice, but x^(1/x)= exp(ln(x)/x) and lim ln(x)/x when x goes to 0+ = - inf, so lim( exp(ln(x)/x) )=0, no ?

__-
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I learned this from professor Penn: floors give inequalities. A related phenomenon is the so called glass ceiling.

emanuellandeholm
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سلام وقت بخیر
حد[[×/1]×] وقتی x میل میکنه به صفر هم از راست هم ازچپ (جدا از هم) چی میشه؟؟

aab
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lnL=lim(x-o) lnx/x
By l hopital rule
lnL= lim(x-o) 1/x
L= e^(lim(x-o)1/x)
L= e⁰
L=1

vikasmanu