A particle of mass 'm' is projected with a velocity v = KVe(Kis less than 1) from the surface ......

Q.42(2) ...--- A particle of mass 'm' is projected with a velocity v = KVe ( K is less than 1) from the surface of the earth . ( Ve = escape velocity) . The maximum height above the surface reached by the particle is --
(a) RK2 / 1 - K2
(b) R( K/ 1-K )2
(c) R( k / 1 + k )2
(d) R2K/ 1 + k

offline centre
RASA CLASSES ALAMBAGH LUCKNOW
Add- Shukla tower first floor near to phoenix mall gate no 3
contact-7985824318