In the arrangement shown in figure the ends \(P\) and \(Q\) of an unstretchable string move down....

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In the arrangement shown in figure the ends \(P\) and \(Q\) of an unstretchable string move downwards with uniform speed \(U\). Pulleys \(A\) and \(B\) are fixed. Mass \(M\) moves upwards with a speed.
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Sir, won't it be v=ucostheta ?? How's it coming u=vcostheta?? In traingle, with u as hypotenuse and v as side opposite to it, and theta as angle between them, cos theta should be opp side divided by hypotenuse which is cos theta = v / u and so v =ucostheta??

TANISHAD_