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Phase Line Examples, Linearization Theorem (Sinks & Sources), Mathematica, First Bifurcation Example

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(a.k.a. Differential Equations with Linear Algebra, Lecture 9A, a.k.a. Continuous and Discrete Dynamical Systems, Lecture 9A. #differentialequations).
(0:00) Many examples of phase lines in this lecture
(0:41) Example 1: dy/dt = f(y) = 3y - y^2 = y(3 - y) (Quadratic right-hand side function)
(2:57) Slope field can be drawn from the graph of f(y)
(4:55) The equilibrium solutions are y = 0 and y = 3
(5:25) The Phase Line with a source at y = 0 and sink at y = 3
(7:12) Nodes can occur as well
(7:45) Example 2: dy/dt = f(y) = y(y-2)(y-4) = y^3 - 6y^2 + 8y (Cubic RHS function)
(8:35) Graph f(y)
(10:55) The slope field
(11:30) The phase line with sources at y = 0 and y = 4 and a sink at y = 2
(11:58) Mathematica for Example 1
(15:20) Animated phase line for Example 1
(16:35) Mathematica for Example 2 (including NDSolveValue)
(19:09) Idea of Linearization Theorem for Example 2
(22:15) Example 3: dy/dt = f(y) = y(y-2)^2 (Cubic RHS with a double root)
(22:41) Graph just touches the axis at the double root y = 2
(23:10) Phase line has a node at y = 2
(24:36) Mathematica
(26:46) Example 4: dy/dt = f(y) = y^3 (Cubic RHS with a triple root)
(27:18) y = 0 is a “weak” source (Linearization Theorem does not apply)
(28:19) Mathematica
(31:24) Example 5: dy/dt = f(y) = cos(y)
(32:32) There are infinitely many equilibrium points on the phase line
(33:28) Mathematica
(35:00) Example 6 (Bifurcation example): dy/dt = f(y) = y^2 + mu
(36:16) How does the phase line change as mu changes?
(37:15) Draw the graphs of f(y) as mu changes
(38:43) Draw the phase lines as mu varies
(39:54) A bifurcation occurs at mu = 0
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