BAD MATH that works

►WEBSITE

►MY COURSE
Prove It Like A Mathematician! (Intro To Math Proofs)

►BECOME A CHANNEL MEMBER

#math #brithemathguy #shorts

Disclaimer: This video is for entertainment purposes only and should not be considered academic. Though all information is provided in good faith, no warranty of any kind, expressed or implied, is made with regards to the accuracy, validity, reliability, consistency, adequacy, or completeness of this information. Viewers should always verify the information provided in this video by consulting other reliable sources.

[BriTheMathGuy]

Check out the Full Vid for more Bad Math! (That works)

[saveerjain]

trig identity is pretty clear on this one tho,
since cos(90-angle) = sin(angle) (or vise versa i’m too lazy to check myself)
it becomes sin^2 + cos^2 of the same angle which is always 1

so 1/1 = 1

[mhm]

Me laughing in asian when he said the question was annoying

[hakeemnaa]

in GRE trest

you can speculate by changing the angles while keep the sum as 90

cos30**2 + cos60**2
1/4+3/4=1
cos45**2+cos45**2
1/2+1/2=1

cos90**2+cos0**2 =1


so in the question, it will be 1/1

[goofy_maxima]

This ain't even bad maths It's CURSED maths

[pengutiny]

I thought you’d cancel out the cos^2s, add the angles and then divide 😭😭😭

[styam_o.]

TEACHER : HOW YOU GET THE ANSWER
ME : JUST BELEIVE ME ANSWER IS 1 🤣

[thinker]

Cos^2(75°) convert 'sin^2(90°-75°), sin^2(90°- 73°)' = 'sin^2(27°), sin^2(17°)' this class 10 identity =1

[kinshuksinghania]

There’s a mathematical hell waiting for people who do these kinds of stuff

[landy]

you skipped one step. when you have cos² over itself, you can take the square root of the numerator and the denominator and then cancel out.

[byrnman]

Just cofunction identities for sin and cos, and Pythagorean identity

[ishanpup]

we can just use the angle sum identity, right?

[Adyioppjh]

You could just use sin^2+cos^2=1 why are you making this so hard damn