Python Programming Interview: Merge Intervals Leetcode ft. Dropbox Software Engineer

In this video, Angie asks Lewin (Dropbox SWE) the Merge Intervals question: "Given an array of intervals, merge the overlapping intervals and return an array of the non-overlapping intervals that cover all intervals in the input."

Chapters -
00:00:00 - Introduction
00:00:50 - Question
00:03:25 - Answer
00:15:44 - Follow-up questions
00:17:39 - Test cases
00:20:05 - Interview analysis

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#softwareengineering #dropbox #coding #leetcode #intervals #tech #entrepreneurship #exponent

[rowvn]

I actually understood this and could code alongside the interviewee. This gives me great hope.

[vishnureddy-az]

The solution can be achieved in O(nlogn) time complexity by leveraging sorting

class Solution:
def merge(self, intervals: List[List[int]]) -> List[List[int]]:
if len(intervals) <= 1:
return intervals
result = []
intervals.sort()
prev = intervals[0]
for i in range(1, len(intervals)):
current = intervals[i]
if prev[1] >= current[0]:
prev[1] = max(prev[1], current[1])
continue
result.append(prev)
prev = current
result.append(prev)
return result

[ngneerin]

These DSA mock interviews are good of exponent