CSEC Maths - Trigonometry Worked Examples

[nicholaschung]

for the 1st question don't get where you got 6 when you only have 8m and 10m

[charmainechambers]

good morning, sir, just a quick question. What if the 60 degree is below the 40 degrees is it the same way to work it out?
sorry i have never done math so am now trying it.

[nikitajulien]

For jan 2009 could i just use the cosine rule then find the inverse?

[ayannalewis]

Sin 0 = opp/hyp = Sin 0 30/1cross multiply MK/10 = MK = 10× sin 30°= MK = 5m

[elliefromtt]

the question from 1999 where the asked to find the size of the angle EDF could i just use the cosine rule since the triangle already has both sides and an angle??

[ayannalewis]

Sin 0= opp/hyp = sin 40/1cross multiply DX/15= DX 15× sin 40 = D= 9.6. Cos 0 adj/hyp=

[c.c]

i realize u do some short hand work when it comes to sine and cosine rule so am asking can i calculate it like how u do in exam and still get my full marks?

[shalinilalchan]

Um the answers you have are wrong for Jan 2009.

[ayannalewis]

Sin 0 opp/hyp= sin 0=6/12= sin 0.5 =0 sin (0.5)=0=3

[c.c]

in the 2009 question u have 6 and there is no 6 on the diagram

[scarlettewhyte]

I don't see the 6 so which one 10 or 11

[jenjensterling]

Terrythe answer is 9.2m instead of 7.2m

[portmorepatrol]

Like u need a better camera sir. Can't make out what is on the screen... only what you writing.

[nicholaschung]

for the 1st question don't get where you got 6 when you only have 8m and 10m