How to Remove Duplicate Elements in List using Python

In this video i will show you how to remove duplicate elements from a list using while loop in python

my setup and gadgets

some terms related to this video
remove duplicates in list python
remove duplicates in linked list python
how to remove duplicate elements in list python
python list tutorial
python list operations
remove duplicate elements from a list in python

tags: #python_list #i_know_python

[PedroCarneiroJr]

a = [1, 2, 3, 3, 4]
print(a)
a = list(set(a))
print(a)
# O(1) algorithm for the same task.
# The set() function converts a to a set which, in turn, cannot have duplicates and returns the set without the duplicates, then the list function converts the set back to a list and returns it.

[ronzmartorres]

That was fast and simple and super useful. thank you

[iyvonneanne]

This was a very great explanation.Thank you!

[مجردرأي-صل]

Thanks, I feel happy because this video help me a lot, I'm from Egypt and I really thank you sir ❤️🌟

[daytoday]

good lesson. thank you very much. I could understand much better the duplicate value program which is explained in this video. because it was difficult to understand in my class to me.

[CodingLovers_]

Apne to ankhe khol di... Ye adbhud tarika btake... Kaha se ate hai aise log...

[jrkagame]

Thank you sir, you've answered by assignment

[scemamil]

result = list(set(list1))

much faster

[shireeshapuli]

How we should take only unique values like output is 9, 8995

[pavansaichintala]

sir can we use list comprehension in code ?

[abhiankur]

I think result=[] is also not required in this program.

[sakshideo]

Can u help me plz i want calculate the no. Of duplicate as 1
I mean if a column contains 1, 1 2, 3, 4, 4, 5
So total no. Of column shoulde be 5

[dharmawangsa]

Lmao i sort it first then check it one by one and append to new list. Thx man i think i should learn more

[lavisharora]

Hello,
if you can tell the program, where I have to take input from the user.

Thanks

[deghedy]

import re
def remove_duplicate_ok(text):

pattern = r'\bOK\b\s+\bOK\b'

return re.sub(pattern, 'OK', text, flags=re.IGNORECASE)

result =
print(result)