Find the number which occurs odd number of times in an Array

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Find the number which occurs odd number of times in an Array. The appearance of the number or the element or the character is odd number of times.
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Love it!! Finally understood!! It would be nice if you explained that in a loop, using odd ^= array[i] would do the whole operation and give the proper result... I didn't really understand that. Thanks!

davidcsidavidcsi
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Thanks a lot sir, you are an amazing teacher!

reyou
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Thank you sir.. Please provide us with its implementing algorithm and also upload more of such helpful videos

tapanjeetroy
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Thank you! I should have found this channel earlier!!

RamisaAnjum
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Nice explanation. Would have been more good if you have explained with binary representation.

ManojKumar-
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A very nice explanation. Could you please help me with the code if there are more elements occurring odd number of times?

abhasahu
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Great but what if the array contains number that greater than 10? Like 11, 13 and so on

kito
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Once you explained logic can you please give whole programme. It will be better in understanding both logic and whole programme at a time. Thank you.

akhileshasare
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Hi Sir,
Please make video to find the two numbers with odd occurrences in an unsorted array

krishnashejul
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aisa krne se last wali element kaise print hogi wo bhi to leader h...???

pkjhabihar
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It can be done in log n using binarysearch

HarshaVardhan-jfsd
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thanks for explaning xor works like addition earlier i was confused about its working

sanketkumar
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What if there are multiple element with odd number of occurrence?

saheb
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please explain compareTo should compare sort string

alluraiaht
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upload more video Sir please related to the tree traverse lower to higher and also upload the operator and looping when use which loop condition plz Sir

pratapsingh-lebr
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The indian man always know this better than anyone

emmaseay
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vivekanand, where is the code for this? Kindly post that also.

gurmeetchawla