AQA Core 4 7.03 Finding the Vector Equation of a Line

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  1. TLMaths
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  6. A-Level
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Комментарии
Автор

Thanks Jack! You explain things so clearly! I've been struggling to get this chapter for ages but I'm finally getting there thanks to your videos. You've given me hope that I may actually get a grade in my A level!

jgreen
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If you have a point that lie on the line, and you have an equation but you are missing the the z coordinate how would you find it (the equation is like: r=[2, -1, 3] + u[-1, -2, p]) how would you do this??

bignate
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What is the difference between a position and a directional vector and what relation do they have to the origin? When would I use the Mu symbol instead of Lambda in the equation? I am confused on what r actually is, if it is a 3 dimensional vector with x, y and z elements, what does it signify because we also have a directional and a position vector in the equation. Thank you

edwarda.
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Would the equation look like r=root(62)[1 -5 6] + [3 2 -5] as you said lamda is the length of line and in previous video you worked it out to be root(62). Thanks

samt
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Is the direction vector essentially the gradient of the line?

WaqasK-Khan