Convert the complex number -sqrt(3) + i in polar form

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In this video, we will learn to convert the complex number -sqrt(3) + i in polar form. Here, i is the imaginary unit.

The link given below is of video verifying the identity cos(pi - x) = -cos x

The link given below is of video verifying the identity sin(pi - x) = -sin x

Other topics of this video are:
-sqrt(3) + i
modulus and argument of -sqrt(3) + i
Find the modulus and argument of -sqrt(3) + i

I, Ravi Ranjan Kumar Singh, have produced this video. All credits of this video belong to me.

  1. Ravi Ranjan Kumar Singh
  2. Find the modulus and argument of the complex number -sqrt(3) i
  3. -sqrt(3) i
  4. modulus and argument of -sqrt(3) i
  5. Find the modulus and argument of -sqrt(3) i
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Unfortunately, once again you made a similar extra long video to find the argument of z.
Since theta lies in the second quadrant, one only has to find arctan 1/root3, no negative sign. The answer will be pi/6. This is then subtracted from pi to get 5pi/6.
Even faster is to put in a calculator pi+arctan 1/-root3, with the negative infront of root3. The calculator gives the answer 5pi/6 immediately.
There's absolutely no reason to represent the problem in polar form, and to know rCosx=-root3, where r=2 and then 2Cosx=-root3, then Cosx=-root3/2, and sinx=1/2, and the identities Cos(pi-x)=-Cosx, and Sin((pi-x)=Sinx and all the other workings are a total waste of time in an exam.
Students should be know the simplest way of working a problem because in an exam the student needs speed. This is a good example of why some students can't finish an exam. There is too much unnecessary work in this video.

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