Solving the IMPOSSIBLE Coin Puzzle !! Hexagon Puzzle with 6 Coins

Tricky brainteaser: IMPOSSIBLE Coin Puzzle
Puzzle : Make a hexagon in just 3 coin moves.
Six coins are arranged as shown in the video.
Your task is to make a hexagon with these coins in just 3 moves.
A move should consist of sliding of a coin and placing it where it can touch two other coins.
A coin should not disturb other coins while moving.
99% people fail to solve this. Give this challenge a try and let me know in the comments section if you managed to solve it.

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[mohammedzubair]

I tried to solve the puzzle using 6 coins but failed even after multiple tries..
Later I watched the solution still was not able to perform the solution live, I watched the solution from the video again and achieved the solution at last.

Great explanation, great video, great contents. @logically yours, you rocked again.

[manusarda]

Who else saw the thumbnail and thought that 'I can solve in 2 moves: 😂

It was challenging after 2 conditions but I was still able to make it. 😎

[pilliozoltan]

For me it was easier to do it backwards. There's only two steps you can do, and one is clearly a dead-end. And the rule is inverted, you can only move a coin if it's connected to two others.

[Hasan...]

*Thumbnail:* What is taught in class
*Video:* What they ask in exams

[Crockist]

A fantastic puzzle, indeed. To solve this, I tried solving it reversed, as the moves were much more limited. For example, the first move would be putting any of these vertices above two other vertices. If I call each vertex in clockwise order A, B, C, D, E, and F, respectively, then I would take A and move it. Moving it so that it only touches 1 coin (which wouldn't be illegal because this is being played in reverse) would not accomplish anything, as it spreads the general shape too thin. That leaves moving it so that it touch B and C or C and D as the only 2 options, and it makes the problem much easier to approach, for me anyway.

If we move A so that it touches C and D, we run into a problem. From here, it's important to keep in mind that a legal coin move must start from a coin which touches 2 other coins. A legal move ends with 2 or more coins touching, so that means these reverse moves must start with that configuration. B and F cannot be legally moved, because they only touch 1 coin. Moving D is legal, but it will inevitably leave groups of two or more coins stranded. You cannot make a final move to complete this pattern. Moving C or E does not lead to any configurations where the puzzle could possibly be solved. This means moving A so that it touches C and D is not the correct move. We must move A so that it touches B and C.

Moving A so that it touches B and C, we now have to make our second move. This means F is not allowed to be moved. C and D would be legal to move, but this would not lead to a solution. Moving one of these would result in 2 or more coins stranded from the general shape. There is no constructive way to move C that would lead to a solution. You could move D around the general shape so that it is touching B and F, but this leaves the only constructive move- Moving E, as an illegal move because E is only touching 1 coin. It would be pointless to move coin A, because any place where we could move it is a move we could have done for our first move. Moving A again would be a wasted move. This makes B the only coin that can be moved in a way that is constructive. Moving B so that it touches C, D, E, and F fills up a decent gap in the shape, so that is what I decided to try first.

After moving B in such a way, we can notice that moving F so that it touches A, B, and C easily completes the puzzle. F is touching two other coins, so this is a legal move. This "unsolves" the puzzle. So then, I did the puzzle in reverse to check my work. Move F so it touches B and E, Move B so that it touches A and C, then move A so that it touches B and F. This is how I discovered this solution, and it seemed to have worked well!

[anmolgandhi]

I dont think that suffice the condition... On making *MOVE 2* your upper coin was not touched by 2 other coins(it was having a single touch of just right coin) until you made your *MOVE 3* ...Observations?

[sadhanaduttapramanik]

Use a small weak magnet to move the central coin out.

*DONE*

Edit: by the way this is also *thinking outside the box* which he wants!

[goguhu]

I found this very simple (did the same moves, but upside-down). Not sure why this would be consider hard/impossible. Given 3 moves you already know that you need to have no more than 2 missing slots in the final hex, so starting point is forced. Then you know it's symmetrical 6-way, so the only coins you need to consider is center, the one off the hexagon. Play it backwards and it's clear how to resolve it, as ONLY possible move is to take any of the 6 and place it to make a 'corner'. No need to try around here at all, as it's all forced on you.

[IsaacKuo]

This is a brilliant and frustrating puzzle. I remember this puzzle from when I was young, but I forgot the solution and so I had a lot of fun and bewildered frustration solving it again.

I don't remember if I gave up on it the first time, but this time I kept at it because I _knew_ there was a solution.

To solve it, I eventually had to give up on thinking logically and just "brute force" the possible first moves. There's essentially only three possible coins to move first, and a very limited number of places to put them. The solution starts off illogically, moving a coin away from a final hexagon position. But then ... aha! It works.

[sixolddereks]

That was a really good puzzle. I had to pull out actual coins to try instead of just visualizing. I was able to solve without seeing the solution by identifying the problems i was facing and coming up with solutions along the way. (At 2:21 in vid and writing this, so not sure if same solution)
- first problem is making 3 moves means you need at least 3 of the original coins already in their spots, and this is only if all 3 moves build into the hexagon. If you need to remove a piece without putting into it's final place, then tou need to start with 4.
- second problem is that you need to remove the "middle" piece of the hexagon before getting to 5 sides or you will not be able to move it without disturbing other pieces.
- next problem I started encountering was building the 5th side of hexagon usually did not touch 2 pieces in mostly all arrangements I tried. So, I came up with the idea of "standing" a piece by moving a coin to leave a different coin only touching 1 piece.
-this led me to starting to abandon the farthest out corner piece. Then removing the "middle" of my now forming hexagon, and moving that farthest out piece to complete the hexagon.
- So, if the coins are numbered 1-3 from top left to right, and 4-6 from bottom left to right. Then, I came up with:
* 1 moves to touch 2 and 3
* 2 moves to touch 4 and 5
* 4 moves to touch the 1 and 2 in a hexagon shape.

[MindfulBytes]

At any point of time, every coin need not be touching at least two coins.

The 'move' actually only consists of sliding the coins such that they touch two other coins after placement. The coins not being moved need not be touching two others.

[JeTeL]

General essence is this; to create required hexagon, you need, at some point, to have coin, which touches only one other coin. How could this be done, when you can slide the coin only to position, where it touches two other coins(„correct move“)? Well, this rule doesn´t prevent you from LEAVING one inaimate coin in solo touching position, by performing „correct move“. Hence your first move must be such, that leaves one of the coins in „single“ touching position (2:44 - most left green coin)

[KingRevvi]

That was solid. I figured it out by realizing many option ended up symmetrical. I worked through the possible moves by force, in a way. Considering symmetry, there are only 3 choices for a start move; one for each coin in the bottom row. Try 1 - move the acute corner first. Try 2, move the middle first. Try 3, move the obtuse corner first. I found it is possible to complete it in 4 moves when moving the middle coin first. Then eventually worked out to move the obtuse corner coin first.

[saurav_kr]

Your videos never disappoint us.👍👍👍 keep it up.

[DesyncX]

It's one of those things that's much easier to solve when doing it than when thinking about it in your head.

[prophetmargin]

Another solution is to move the two middle coins simultaneously so they both meet and complete the top part of the circle and then move the coin at the bottom far left to the right so it completes the circle on the bottom!

[curiouscat]

Use two fingers to move the coins, and do it in two moves. First move the central coin and hold it aside. Next move the bottom left coin with the other finger. Now simultaneously move both the coins into their required positions on the hexagon. This satisfies all the rules. It isn't mentioned that the first move has to be completed before starting the second move.

[justaconcrete]

Omg my first assumption is correct, i just move my phone to the right a little bit and i tried like this video. I thought it wasn't the answer cus every riddle here is used to have brilliant solutions and i ain't that person. 😊

[mohit]

Your videos always includes thinking out of the box. Love your riddles very

[Thomas]

No, it's just matter of two moves, just place first coin from second row and second coin on first row above first row of