Finding The Zeros of Fourth Degree Polynomial

👉 Learn how to find all the zeros of a polynomial by grouping. A polynomial is an expression of the form ax^n + bx^(n-1) + . . . + k, where a, b, and k are constants and the exponents are positive integers. The zeros of a polynomial are the values of x for which the value of the polynomial is zero.

To find the zeros of a polynomial by grouping, we first equate the polynomial to 0 and then use our knowledge of factoring by grouping to factor the polynomial. Next, we use the zero-product property to evaluate the factored polynomial and hence obtain the zeros of the polynomial.

Recall that the zero-product property states that when the product of two or more terms is zero, then either of the term is equal to 0.

Organized Videos:
✅Zeros of a Polynomial by Factoring
✅Zeros and Multiplicity of Polynomials | Learn About
✅How to Find all of the Zeros by Sum and Difference of Two Cubes
✅How to Find all of the Zeros by Grouping
✅How to Find all of the Zeros in Factored Form
✅How to Find all of the Zeros by Factoring 5th Degree
✅How to Find all of the Zeros by Difference of Two Squares
✅How to Find all of the Zeros by Factoring 4th Degree
✅How to Find all of the Zeros of a 3rd Degree Polynomial
✅How to Find all of the Zeros Without Factoring

Connect with me:

#polynomials #brianmclogan

[brianmclogan]

glad I could help, its fun when those things finally start to make sense

[liankhai]

LOL my math teacher is too lazy to teach so she told us to watch this video

[Bigschmitt]

Thank you this helped a lot! I also love how you dont even edit out you calling out your student for not paying attention. I was laughing my ass off at that.

[Riverbend]

I'm a sophomore in college, and the professor teaching my differential equations course linked this video in our study materials. Thanks for putting it out there. It had been so long since I took an algebra class that I had forgotten how to do this, but this was a really approachable way to relearn it.

[deedeeOWL]

👍🏼 I like how the teacher have include all zeros (even the imaginaries) so students see the big picture, and think in terms of Complex: Real and Imaginaries

[brianmclogan]

I don't know why I said you couldn't factor by grouping for this problem. You certainly could. I think I was more concerned with showing how to solve using rational zeros

[khushibarnawal]

Sir your videos are easy to understand... I wish I could study with you in my school.

[kelvink]

some of those kids had no idea how blessed they were to have a good professor

[those.gamers.]

ah thank you, my math teacher expected us to do a packet with a question like this and didn’t teach it lol

[vnoscope]

Was going crazy trying to figure out how to factor these, appreciate the help 💪

[mt]

I'm taking engineering and watching this guys vids for finals, really shouldn't have skipped so many lectures...

[fedorshcheglov]

Watching this during quarantine, very helpful when you can't reach your teacher! :)

[brianmclogan]

When graphing this polynomial see that there are no real roots. Meaning their are no real zeros you can solve for(x-intercepts)

[Starscrayper]

With your help, I'm able to cram for my college algebra test, and I am infinitely grateful for this.

[kmillz]

Brian, your videos continue to help me everyday. Thank you for doing what you do...and please continue to do so.

[yzel]

Your channel is a life saver thank goodness I found these videos

[aliris]

I'm a parent struggling to explain "CC" math to my kid and wow do I appreciate your videos. Thank you!!!

[jerryfan]

At 8:46 shouldn't it be i*sqrt of 2? This way, when you put "i" in the equation, it will change sqrt of -2.

[oskarlindelof]

I solved it using factoring, this is how I did:

z^4-4=(z^2+2)(z^2-2)
-z^3-2z=-z(z^2+2)

z^4

z^2-z-2=0 or z^2+2=0. Using the quadratic formula you can then determine that the roots are -1, 2 and +/-sqrt(2)i.

[Hahaalot]

Yo my nigha! Literally in college Algebra and used this video for my homework. Completely forgot parts because of spring break. U's the real MVP! Thanks my guy! :)