Java Streams Interview Question - 07 - Find Max and Min Numbers using Streams

Java Streams Interview Question - 07 - Find Max and Min Number using Streams

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[anitsarker]

We can also use this using lambda:

int result = list.stream().max((e1, e2) -> e1-e2).get();
int result = list.stream().min((e1, e2) -> e2-e1).get();

[rajnikanthofficial]

same for min with min it will be easy thi way

[nikunjpatel]

This is another way of solution:

List<Integer> list1 = Arrays.asList(-1, 0, 1, 3, 10, 20, 30, 15, 1, 13, 1, 2, 2, 10, 40, 19, 3);
Integer maxnum = list1.stream().reduce(1, (a, b) -> a > b ? a : b);
System.out.println(maxnum);
Integer minnum = list1.stream().reduce(1, (a, b) -> a < b ? a : b);
System.out.println(minnum);

[Srikanthb]

we can use this better than others

-> value).min().getAsInt()));

[watchmeplayit]

how about:

List<Integer> list6 = List.of(10, 20, 30, 25, 21, 0, 30, 100, 999, 3, 33);

Optional<Integer> max = list6.stream()
.max(Integer::compareTo);

Optional<Integer> min = list6.stream()
.min(Integer::compareTo);

[postoronnii__]

It can be done with reducer() and method reference:
Integer result =

[gottepavani]

In java we use that for converting an integer to string

[jitendrapatil]

SummaryStatistics is the best way to find out max, min, average etc.

[maheshuma]

We can simply Write : IntSummaryStatistics collect 
Ouput is : : IntSummaryStatistics{count=20, sum=390, min=10, max=29}

[shaikjareena]

List<Integer> o = List.of(1, 20, 30, 4, 4, 30, 30);
Integer i =
System.out.println(i);

[ashutoshsingh-uhio]

Please let us know the time and space complexity of these solution also in comparison with the best solution, as interviewer focus more on that

[RaahithyaYadav]

@naveen how to find second largest number through stream

[jaleelpasha]

How about this one?
OptionalInt maxOptional =
System.out.println("Max = "+maxOptional.getAsInt());