A particle moves in x-y plane with a velocity vec v =2y hat i +4 hat j . Equation of the path follow

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A particle moves in x-y plane with a velocity vec v =2y hat i +4 hat j . Equation of the path followed by the particle is

(1) x = sqrt(y)

(2) y = sqrt(x)

(3) 4x = y ^ 2

(4) 4y = x

A particle is moving with velocity v = K(𝑦𝑖 ̂+𝑥𝑗 ̂), where K is a constant. The general equation for its path is:
y = x² + constant
y² = x + constant
xy = constant
y² = x² + constant

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Thanks u sir 🙏app hamara liye etne raat mein bhi jag kr video upload karte hein .I am very grateful to you 🙏. thanks sir

lipsamohanty
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Sir daily kitne question solve krne chaye physics ke liye

SanketKhade-le
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This question plz...A man is walking on a horizontal road at velocity 5 km per hour and the rain appears to be falling vertically at 5km per hour to him.the magnitude of velocity of the rain with respect to the ground is

makefuture
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Sir aap har chapter ka topic, uss topic me bahut saari numerical karwaoo
ex:- projectile motion (motion in plane)
Uss me he bahut saare numericals questions and baki chapters ka bhi topic wise numerical karwaoo and neet me Jo repeated numerical hai wo bhi karwaoo bahut help hoga neet me haame it's request plsee sir 😭🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

RFAGT
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Why was integration used to find the value of y, not differentiation?

shree
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Sir aap please ak chapter vise question series aplod kijiya na

PravinKeshav-ezoj
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If you divide, you'll get ans faster

GoogIe-ingu