CENTER OF MASS in One Shot: All Concepts & PYQs Covered || JEE Main & Advanced

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Dive into the World of Center of Mass in One Shot! 📚🎯 Join us for a comprehensive session covering all concepts and previous year questions for JEE Main & Advanced. Master the intricacies of Center of Mass with this power-packed guide. Boost your preparation and excel in your exams!
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MANZIL 2024 Batch Description :
🚀 This batch is Completely FREE for all the students aiming for JEE MAINS 2024
🚀 Will cover the complete JEE Syllabus of Physics, Chemistry & Mathematics
🚀 Each Class will be LIVE on our JEE Wallah YouTube Channel
🚀 6 Days Scheduled classes with One lecture each day
🚀 Chapter One Shot will be conducted with PYQ’s
🚀 The Weekly Schedule will be provided in the community section of JEE Wallah’s YT Channel & Announcement section of the PW App
🚀 Class Notes in PDF Format will be uploaded on our PW App
🚀 Daily Practice Sheet with Text solutions will be provided.
🚀 Weekly Tests based on the Syllabus of that week will also be conducted.
🚀 Classes will start from 22nd November 2023
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📌 𝐉𝐄𝐄 𝐖𝐀𝐋𝐋𝐀𝐇 𝐒𝐎𝐂𝐈𝐀𝐋 𝐌𝐄𝐃𝐈𝐀
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📌 𝐑𝐄𝐂𝐎𝐌𝐌𝐄𝐍𝐃𝐄𝐃 𝐂𝐇𝐀𝐍𝐍𝐄𝐋𝐒 𝐅𝐎𝐑 𝐘𝐎𝐔
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📌 𝐏𝐇𝐘𝐒𝐈𝐂𝐒 𝐖𝐀𝐋𝐋𝐀𝐇 𝐒𝐎𝐂𝐈𝐀𝐋 𝐌𝐄𝐃𝐈𝐀
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⏳ 𝐓𝐢𝐦𝐞𝐬𝐭𝐚𝐦𝐩𝐬
00:00 - Introduction
11:40 - COM of discrete systems
44:48 - COM of system of particles
1:06:09 - COM of distribution of mass
1:23:28 - COM of symmetry bodies
1:40:23 - Additive systems and negative systems
2:18:31 - Shifting of COM
2:24:30 - Velocity and acceleration of COM
3:30:40 - Motion of person on Planck or boat
4:03:53 - Conservation of linear momentum
4:12:16 - Jumping from cart/Recoil of gun
4:42:11 - Explosion problems
5:07:37 - Collision and types
5:56:06 - Velocities after Collision
6:27:18 - Bouncing of ball
6:41:39 - Oblique Collision
8:14:29 - Thank You Bachhon!
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#CenterOfMass #JEE #JEEWallah #PhysicsWallah #PW #ManzilSeries #JEEBatch #JEESeries #Manzil #Manzil2024 #Physics #Pyqs #JEEConcepts #OneShot #CenterOfMassPhysics

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[01:01:53]This section discusses how to calculate the center of mass.

- The right of 9 centimeters to the left of 9 centimeters is mentioned.
- The center of mass is calculated by dividing m11 plus 3/2 into 0 plus 4 into 5/2 by the total mass.
- The positive value is obtained for the position at 2 centimeters above.
- The options are discussed, but it is not clear which one is the correct match.

[02:03:42] This section discusses the calculation of lengths and coordinates for a solid hemisphere.
- The length of the solid hemisphere is 3.
- The length of the other part is negative 3.
- The coordinates will be negative if added to the solid hemisphere.

[06:11:28]This section explains the concept of center of mass and how to calculate it using the formula.
- To find the center of mass, divide the sum of the products of mass and velocity by the sum of the masses.
- The common velocity of two objects can be calculated using the formula (m2u2 + m1u1) / (m1 + m2).
- In perfectly elastic collisions, if the value of e is zero, the loss will be 1/2 m1 m2 divided by the sum of the masses.

[07:13:19]This section explains the concept of collisions in the context of center of mass.
- The video mentions that after the second collision, the object will move towards V.
- It states that the third collision will occur at point A.
- The subtitles mention that there is no question V.

SanjeevKumar-umyz

He is the teacher in which class i never become bored

nurhinabegum

1:05:32 2 ques hw 1:17 2 ques hw 2:17:40 2 ques hw 2:33 hw 2:48:00 hw 2:53:35 hw all homework ques of com

divyagarg-isfx

Best ever revision sir ♥️🥰
Thanku so much for this fantastic session 🥰🥰🔥
U killed it👊🥳

utkarsh_SR_pathak

RJ SIR GOD OF PHYSICS Respect sir's dedication
All The Best All Jee Aspirant 2024

MrAlakhPandeyPW

Self Rvn
58:54
1:23:09
1:37:21
1:51:27
1:58:42
2:17:43
2:31:28
2:37:02
2:50:03
2:53:16
3:50:35 VVi ❤ Boat Man 3:54:00
3:57:59
4:32:50 Retry VVI type 4:37:37
4:51:01 ❤
5:02:52
5:07:14
6:25:13
6:38:49
7:07:56
7:15:06 retry ❤
7:17:50
7:22:03 retry ❤
7:27:56
7:41:25
7:45:19
7:50:42 ❤
7:56:48
8:12:29 rewatch Qtn

skyshorts

Thanks a lot sir for ur dedication...u made us understand the concept very clearly...we have the confidence of solving the problem..🥰🥰❤️❤️❤️🙏🙏🔥🔥🔥🔥

ScaryStriker

Break:- 02:59:50 - 03:14:30
05:42:00 - 05:56:00

SarthakSingh-

Lecture start watching 6.9 k after complete lecture 2.3k ❤
Remember
Why you started Journey ❤😊

prashant_NITian.

HW answers according to me.

DISCLAIMER---> IT MAY BE INCORRECT.
1:05:43 C 7/12m, √3/4m
1:05:44 A 13/8Lx, 5/8Ly
2:17:49 B
2:17:51 23
2:33:03 A m1a/m2
4:01:21 A 5/4 m towards right
5:07:20 6

Pls check my answers and if any is wrong then pls reply.

Olymoiads

Thank you so much sir ❤
As always, you just nailed it sir✨✨
Loved the session, best ever revision session on COM and collisions !!!
LOVE YOU SIR ❤❤

sonammishra