The 5 Hardest Circle Theorem Exam Style Questions | GCSE Maths Tutor

A video revising the techniques and strategies for answering exam style questions on circle theorems (Higher Only).

This video is part of the Geometry module for Circle Theorems in GCSE maths, see my other videos below to continue with the series.

These are the calculators that I recommend:

Don’t forget to check these videos out:

🔹 Watch the video
🔹 Make notes
🔹 Practice the questions
🔹 Mark your work
🔹 Review what you have learnt on the exam questions

Part 3 - Circle Theorems using Algebra - Coming Soon!

Please like ✅ please comment ✅ please subscribe ✅

Enjoy the video!

Follow me here:

Music: Over N Over
Musician: Not The King.👑

[ggwzyyx]

I got moved into a higher set because of how helpful your youtube channel was, thank you so much!

[someone...]

For those highly able students aiming for a grade 9 in maths, and not really sure of what to do: well ur at the right place. Watch all of his top hardest gcse question videos, and im ngl ur basically guaranteed that 9! Try to work through all of the problems urself before u watch his solutions, and for each video, try to spot the pattern, as usually these trickier grade 9 questions will have certain patterns as per topic, which if u can spot and acknowledge will massively help u figure out how to approach the exam question whatever it may be! Good luck to all watching and wish everyone a grade 9!

[_liampitigala_]

You sir, have made me motivated for my math GCSE's. Please sir make a math website.
You're so underrated, i'm going to shout your name in my math GCSE exam for you

[numskulll]

Nice problems!
Some alternative approaches to consider:
Q1: ACB = 56 deg (alternate segment); CBO + CAO = ACB (due to isosceles triangles CBO and CAO), hence CAO = 21 deg
Q4: BOC = OBA + OAB (external angle of a triangle)
Q5: y = BAD = BDE (alternate segment) = = x + 90 deg, hence y - x = 90 deg

[paperlytical]

These videos are amazing! They've helped me understand maths at TON!!! Because of these videos, I've improved from 4s to 7s for EDEXEl and its all thanks to you.

[oliviaaa]

listen to me i have literally based my whole gcse revision on your videos. ong you are so underrated and take my word when I say you're gonna blow up very fast very soon. thank you so much we all appreciate you.

[alisha]

i honestly can't thank you enough for these videos you literally saved my maths gcses. thank you so much for making these lessons free as well thats really useful

[Ryan-bmlc]

i initially understood none of these but you explain it so fluently in such an easy-to-understand way that i understand how to do it almost instantly

[niveankoneswaran]

It's so much easier to understand when you explain it.
Thank You!

[PsychRightyt]

Really helpful as I have a test on this in a week - amazing work👍

[muhammadaizaz]

This teacher is legend. Best teacher ever. Thank u very very very much

[anjanaajmera]

In the first qs, u could have directly gotten angle BCA as 56 from the alternate segment theorem, and angle OCA would've become 56-35=21. Triangle OCA is iscoceles hence angle CAO=21. simple. cheers

[MKhan-qelp]

great video. geometry is a tad difficult but you know your stuff.cheers for this.

[Mahle-fb]

I like how you explain, step by step getting to a solution. Thank you .

[mohammadtaosif]

I just want to say thank you. These videos are super helpful!

[Mathspaperksks]

Really nicely explained video congrats on surpassing 58k!! You have surpassed TLmaths and he's a big YouTuber as well!! Nice one sir!! Keep grinding!!

[pragyaprak]

In the third question, the one which has an answer of 21.6cm, I don't get why you wouldn't do the arrowhead method? If we drew a line from A to B and another from C to B, we would get the arrowhead shape and half the angle COA (112.5...) which would give us an answer of 56.3cm to 3 sf. I understand you can't assume that it's an arrowhead but the video did at 8:56. Any help is appreciated!

[shins_clips]

This is what I was looking for! Like and subbed

[not_today_x]

Last Question alternative method (lmk if im wrong lmao)
<BCD=<ADF (alternate segment theorum)
<BCD= 90-x (tangent meets radius at 90 degrees)
So <ADF = 90-x
<ADF + y = 180 (opposite angles in cyclic quad add to 180)
90-x +y =180
-x+y =90
y-x=90

[Masowe.]

thank you sir. i moved from grade 6 now 1 mar away from grade 9 with your videos and 1 week away from exams but i want a 9