'Show that the function `f: N-N` given by `f(1)=f(2)=1` and `f(x)=x-1` for every `xgeq2`

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"Show that the function `f: N-N`
given by `f(1)=f(2)=1`
and `f(x)=x-1`
for every `xgeq2`
, is onto but not

one-one."
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How is it not one one function when both f(1) and f(2) = 1 both x is equal to 1 then it's one one right?

RoastMeNot