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using keyboardInterrupt exception #shorts
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This is a simple code to:
1. Use a try-except statement
2. Recognise a KeyboardInterrupt and print "Interrupted"
Link to the code:
1. Use a try-except statement
2. Recognise a KeyboardInterrupt and print "Interrupted"
Link to the code:
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![Python Error [PART-2]-](https://i.ytimg.com/vi/cyWPD_Ycjho/hqdefault.jpg)
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