I Will Show Your FACE In This Video..

I Will Show Your FACE In This Video..

#Shorts #ImposterBruh #Trending

[themusicman]

Yeah lol I just see a reflection of me too

[elfwithantlers]

My friends: True! I see my face!
Me: Lol, my screen is too dirty!

[yeavLikesStockAndroid]

Him: **tries to show my face using a black screen**
Me who has a matte display: Nice try.

[lissygomez]

he will never forget to say "yes guys" :]

[Sans-the-short-skeleton]

Face reveal
Edit: I have to give credit to the last part 🤣🤣🤣🤣🤣🤣

[catinpringle]

me:staring at the mirror for 20 minutes to see if i can see my face

[ajibsempoi]

Ofc we can see we face bc is dark 😂😂😂😂

[charlesranleecallo]

'FUN FACT:he never forgets to say yes guyss'

[nwebh]

Him: **shows a black screen to show my face**
Me on a pc: *i don't see anything*

[prabasundaram]

You 'heard it right never gets old'

[uniquethebaddest]

Ha ha very funny I literally didn’t see my face from the black screen because I wasn’t looking and then I looked and I still didn’t see nothing 😂😂😂😂😂😂😂

[meghachannel]

Oo nice I thought that you're going to show our face in that mirror but at last you show that in full black screen 😂

[leenakhabagadi]

Fun fact: he never forgets to say “yes guyss

[SpifeX.X]

Any complex reflection group is a product of irreducible complex reflection groups, acting on the sum of the corresponding vector spaces.[1] So it is sufficient to classify the irreducible complex reflection groups.

The irreducible complex reflection groups were classified by G. C. Shephard and J. A. Todd (1954). They proved that every irreducible belonged to an infinite family G(m, p, n) depending on 3 positive integer parameters (with p dividing m) or was one of 34 exceptional cases, which they numbered from 4 to 37.[2] The group G(m, 1, n) is the generalized symmetric group; equivalently, it is the wreath product of the symmetric group Sym(n) by a cyclic group of order m. As a matrix group, its elements may be realized as monomial matrices whose nonzero elements are mth roots of unity.

The group G(m, p, n) is an index-p subgroup of G(m, 1, n). G(m, p, n) is of order mnn!/p. As matrices, it may be realized as the subset in which the product of the nonzero entries is an (m/p)th root of unity (rather than just an mth root). Algebraically, G(m, p, n) is a semidirect product of an abelian group of order mn/p by the symmetric group Sym(n); the elements of the abelian group are of the form (θa1, θa2, ..., θan), where θ is a primitive mth root of unity and Σai ≡ 0 mod p, and Sym(n) acts by permutations of the coordinates.[3]

The group G(m, p, n) acts irreducibly on Cn except in the cases m = 1, n > 1 (the symmetric group) and G(2, 2, 2) (the Klein four-group). In these cases, Cn splits as a sum of irreducible representations of dimensions 1 and n − 1.

[shaheenwaqar-ozln]

That's crazy i see myself in the reflection 😂😂😂

[Marcodeo]

I Saw my Face but it was the reflection

[kayleepressley-tlxo]

I saw my face but it was just reflecting ha ha that's funny🙄

[neilmcgivern]

I just saw the reflection of my face that’s all from Daisy ❤❤❤😂😂😂