Part 12 | Pattern Printing | Python Malayalam Tutorial Series

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This is the twelfth video of our "Python Malayalam Tutorial Series". In this tutorial, we are explaining more about python pattern printing

Python Malayalam Tutorial Series:

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Part 1:

Part 2:

Part 3:

Part 4:

Part 5:

Part 6:

Part 7:

Part 8:

Part 9:

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Part 11:

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prefectly understand what you teach great job sir....

abinbiju
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i=1
a=1
k=0
while i<=5:
while a<=5:
k=5-a
print(" "*k + a*'* ')
a=a+1
i=i+1

I did it own my

TheOldAge-kscj
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i = 1
while i <= 5:
print ("a"*i)
i += 1

arunprakash-umwd
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i =1
while i<=4:
j=1
k=1
while j<=7:
if j>=5-i and j<=3+i and k:
print("*", end='')
k = 0
else:
print(" ", end='')
k = 1
j += 1
print()
i += 1

abincjoseph
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i=1
while i<=5 :
print(" "*(5-i), end=" ")
j=1
while j<=i:
print("a", end=" ")
j=j+1
print()
i=i+1

AshithKP-jqzj
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K=1
While k<=5-i:
K=k+1
Print (end=' ')

nanduraj.
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x=1
while x<=5:
a=4
while a>=x:
print(" ", end="")
a=a-1
y=1
while y<=x:
print("@", end=' ')
y=y+1
print("")
x=x+1

Sir pause cheythu cheyyan parannappol anikku piramid kittiyathu ingene code cheythappozhanu . Njn cheythanu kozhappam indoo

Sir njn coding padikkan start cheythu sirtte class nlla ubhakarapettu... thanks 🙏

arbaazbinafsar
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I did it myself and i got this: -
a
aa
aaa
aaaa

saviostephen
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n = int(input("enetr a number:"))
i = 1
d = n + 1
e = d/2
while i <= n:
j = 1
k =1
while j <= 2 * n - 1:
if(j>= d - i) & (j<= e +i) & k:
print("*", end="")
k = 0
else:
print(" ", end="")
k = 1
j = j+1
print()
i = i + 1

abincjoseph
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s=4
j=1
while s>=1 & j<=4: # "s" -space, " j"- number of a to be print
print(end=" " * s)
print( "a " * j)
j=j+1
s=s-1

sanjujayan
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