Lec-69: TCP Congestion Control in Computer Networks in Hindi

TCP Congestion Control in Computer Networks is explained here in this video.
TCP detects congestion when it fails to receive an acknowledgement for a packet within the estimated timeout. In such a situation, it decreases the congestion window to one maximum segment size (MSS), and under other cases it increases the congestion window by one MSS.

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[ayushisharma]

Just wanted to put this here in case anyone was wondering- we divide the congestion window size by 2 to get the threshold. This has nothing to do with the fact that the MSS is 2KB in this question.

[rockrk]

it's been 4 years still your playlist is best on youtube!!

[GeerishaAcharya]

Literally dedicated Teacher...Thank you so much sir..You are "चाणक्य" for computer science students..🙏🙏

[architlatkar]

Hello Sir, i really love your videos for the short and to the point explanation. Here i want to point out to two mistakes in this video.
1. You are using TCP RENO method for congestion control. If it receives 3 duplicate ACKs then the threshold is half of current value and the transmission starts at threshold+3. You have started it from threshold itself which is not the case.
2. There are 11 RTTs so the answer should be 1100 not 1200

[awdheshkumarravi]

11 and 8 segment respectively.... I think answer 1100 n 800, , ...good qstn for practice

[arpangupta]

THANK YOU SO MUCH SIR.
PLEASE UPLOAD THIS KIND OF VIDEOS ASAP.

[shivangagrawal]

Genuinely, a gr8 teacher hatts off to u sir

[chetnamarwaha]

Seriously very well explained.. Thankyou so much bhaiya .. need more such videos.. keep posting..Your videos are very very helpful.. God bless you a lot ☺️

[kumarrajavarma]

Just Superb Sir No more Words.Thanks For ur efforts sir very Helpful Sir..!!!

[ankitsingh]

you must tell which protocol you are using for congestion control, TCP Tahoe or Reno as they reacts differently for 3ACK case

[apnikakshafc]

00:01 The question is about TCO congestion protocol.
01:47 Congestion control in TCP works in three phases.
03:17 Congestion can be severe or light depending on the number of acknowledgements received.
04:52 Slow start and exponential growth followed by linear growth in TCP congestion control
06:32 Congestion is detected due to 3 acknowledgements.
07:57 Using linear phase to find the threshold value and determining the number of segments to send.
09:29 TCP congestion control and finding total number of RTTs
11:08 The answer to the question varies between 1100 to 1300.
Crafted by Merlin AI.

[datadhawan]

Answer must be 1100 msec for time out
And 800 msec for 3 duplicate acks

[bajrangverma]

great job sir...easy and nice explanation

[shima]

Sir Completed all your computer network classes... Sir Please add mac protocol in detail

[sajansekhu]

thnkss alott ji....siraa bro....Stay blessed...

[dgateacademy]

11*100 =1100 is correct, RTT is (2 to 4) count is 1, like this way 11 RTT.

[sashankpatnaik]

Sir, in the first case you used TCP tahoe and in 2nd case you used TCP reno. Any specific reason for that?

[rakeshyadav-mulk]

thank u for all yr effort.
but i think 11 rtt will b there in case 1
and 8 rtt for case2

[debabratatah]

Sir additive increase means increase by 1 according to geeksforgeeks. is it true?

[hunzlahmalik]

You teach very well to clear our concepts. But in this video you didn't explain the congestion control and congestion control principles. Student will understand much better if you first explain these things and then move to the questions. Thanks