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Algebra: Factor ax^2+bx+c Fast and Easy

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Here we discuss the easy and fast way, for me, to factor ax^2+bx+c.
This method could be faster than box method, guess-and-check method, or diamond method (or ac method) with factoring by grouping, and can be used to find the roots of (factorable) quadratic equations quickly.
This is the same as slide-and-divide factoring technique but be careful when the terms have a common factor. For example: if we apply slide and divide immediately for 4x^2+2x-6 then we get x^2+2x-24=(x+6)(x-4)
(x+6/4)(x-4/4)
(x+3/2)(x-1)
(2x+3)(x-1)
but the last expression is not equal to the original trinomial.
The good point in my video is that you know that ax^2+bx+c=a(x+M/a)(x+N/a), and this will give you a trick in solving quadratic equations.
This method could be faster than box method, guess-and-check method, or diamond method (or ac method) with factoring by grouping, and can be used to find the roots of (factorable) quadratic equations quickly.
This is the same as slide-and-divide factoring technique but be careful when the terms have a common factor. For example: if we apply slide and divide immediately for 4x^2+2x-6 then we get x^2+2x-24=(x+6)(x-4)
(x+6/4)(x-4/4)
(x+3/2)(x-1)
(2x+3)(x-1)
but the last expression is not equal to the original trinomial.
The good point in my video is that you know that ax^2+bx+c=a(x+M/a)(x+N/a), and this will give you a trick in solving quadratic equations.
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