U Tube Manometers - Pressure, Density & Height of Oil & Water - Fluid Mechanics

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This physics video tutorial provides a basic introduction into U Tube Manometers with two liquids. It explains how to calculate the height of the oil column as well as the height of the water. In addition, it explains how to calculate the density of an unknown fluid using a u-tube manometer. This video contains 3 practice problems for you to work on.

Mercury Barometer Problems:

Open Tube Manometer:

U Tube Manometers:

Archimedes Principle & Buoyant Force:

Buoyant Force of Helium Balloon:

Physics - Intro to Buoyancy:

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Apparent Weight and Apparent Mass:

Fractional Volume of Submerged Object:

Hydrometer Physics Problems:

Volume Flow Rate and Mass Flow Rate:

Equation of Continuity:

Bernoulli's Equation:

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Torricelli's Theorem & Speed of Efflux:

Venturi Meter Problems:

Dynamic Lift Force:

Viscosity of Fluids and Velocity Gradient:

Full-Length Videos and Worksheets:

Physics PDF Worksheets:
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You are divine sir, I always enjoy your tutors

lilywhite
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Most helpful video to explain this equation, amazing man !

saraism
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I had an exam today and you helped me passing it, thank you so much for your amazing videos, your teaching skills are amazing and you are intelligent as well. God bless you ❤️❤️

ranavantaepurple
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You certainly made physics easier with this amazing vedios, Thanks a lot👍

rahulg.c
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Thank god for your channel, I just barely managed to write the test thanks to you.

desterotheking
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and now I am ready for my final. best explanation of the topic i found. Thank you.

Chaoddity
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thanks you helped me understand this :)

kenrock
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Thank you Sir. Really a very helpful video

aswinp
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I still have a question ; what happens when the U tube Manometer contains three or more liquids? How to calculate the height or density of one of the liquids.

nkebeshaclaudine
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i have a question 🤚🏻 for #2 as the height of water above the reference leveldecreases, the specific gravity of oil decreases as well??

teendiversph
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this is so much more understandable than my ChE professor makes it.

MonkeyDPickle
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You need to convert cm to m first with these formulas. The density is measured in kg/m3, you can't now do the calculations with the height in cm, the SI base units won't make sense. Either convert kg/m3 to kg/cm3 or cm to m. cm to m is much easier.

kashaka
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how can we cancel out Patm if it acts on different heights, on the right side it will be stronger than on the left since the height of vertical air block is bigger, the difference will be very small but there will be difference, on the left side Patm=air density*g*h, and on the right side Patm=air density*g*(h+d), d being the height difference between 2 sides

smd
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since you're using the heights in cm, shouldn't they be converted to m for correct densities to be found in kg/m³

alishaashraf
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We usually equalize the pressure on a same liquid
So in the first interface, can we do that, since there are 2 different liquids

Sukie_
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Sir you must not neglect, it must be dimensionally consistent

manolitocatarroja
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can someone tell me why isnt this taken into account when calculating the pressure transmission through a fluid

randominus
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Thank you . My books explanation is like 💩. But you helped me . Hope this type of ques come in my exam ✌️💯

PNK_DIARIES
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What if there's an ratio included inorder for to find h2???

jimmyevesa