7.5.2 Poynting's Theorem

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7.5.2 of Griffith's Introduction to Electrodynamics 2nd Ed

Poynting's Theorem introduces the useful Poynting Vector, S.

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I appreciate you explaining it in more detail than the book. Thanks!

woof.woof.

if delS>0 d(Um+Uem)/dt<0, if energy flows out of the system then the time rate of change is negative since energy is leaving the system. Missing minus since around 15:30.

tuckerhartland

Thank you!
at 15:40 there's a negative sign besides the divergence of S.

BlueRobair

Great job, very thorough. All I could think about was how much my hand would be hurting, haha.

ericberlo

Why is dW/dt the total work? What happens in the transition at 3:45 where you put an integral on the right hand side and set dW/dt on the left? Seems to make no sense?

numbo

Again jonathan sr you rocked the topic so helpful sr from india🎊🎄😃

sunnypala

Thank you, it really cleared my doubt.

lazyaditya

The clock ticks in the background are driving me insane…
Thanks for the video, though. Really helpful.

Blobbingmicaminoporvida

Same reason as you had for the minus sign on divJ=-d rho/dt

tuckerhartland

Thank you very much for yor great help, it is very useful

sevgiolmez

It's very understanding..video..really good

rashmidevanga

I hate the sound of that marking pen rubbing on the paper... Really trying to resist. What's wrong with me?

lameitout

2:55 magnetic field does not work you said, why please? is'nt it we have magnetic field and electric field?

tarikeng

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