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ะ ะตะบะพะผะตะฝะดะฐั†ะธะธ ะฟะพ ั‚ะตะผะต
ะšะพะผะผะตะฝั‚ะฐั€ะธะธ
ะะฒั‚ะพั€

50:42 Write โˆš200 = 10โˆš2 & โˆš162 = 9โˆš2 for easier calculation

lordJD
ะะฒั‚ะพั€

52:00 Here's the easier method...
Take ratio of T=โˆš(2H/g) and T - 0.5 = โˆš(2ร—81/g)
We know value of H and so we can find T.. by putting T in any of the equation, we can get g...

okok...
ะะฒั‚ะพั€

16:40 relation writting btw H and u
23:00 relative position ke graphs
47:00 diff planet ki gravity
1:15:00 perpendicular kb hogi velocity
1:23:00 relative velocity
1:26:00 horizontal landing on an inclined plank

raj_divyanshu._
ะะฒั‚ะพั€

at 36:07 the ratio of t2 will be 180/110

siyasinha
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Rj sir on 2021 and Rj sir on 2023 is like a day and night difference, from funny and smart to mature and intellectual love u sir ๐Ÿ’Ÿ

tapashisfoodcorner
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at 51:26 we can make calculation easy
2[/200 - /162]
2[10*/2 -9*/2]
2*/2[10-9]
2*/2 = /g
squaring both side
4*2=g
g=8
/ represents underroot

suryanshgoyal
ะะฒั‚ะพั€

Let's rock pwians ๐Ÿซก
Most awaited series has been started ๐Ÿ’ฅ๐Ÿซถ

bhagwandass
ะะฒั‚ะพั€

Sir at 36:23 you put the value wrong T1= 180/50 not 120/50 please check

Trendingmeme
ะะฒั‚ะพั€

PW TEAM PLEASE MAKE A PLAYLIST FOR THIS BATCH โค๏ธ SO THAT LECTURES ARE ARRANGED

ayanaslam
ะะฒั‚ะพั€

4:24 faster way to crack question is by using v2-u2=2as(as acceleration is constant) by selecting any two points on the graph.

awakenerthe
ะะฒั‚ะพั€

11:45 ithink there is a smart way also
from given graph
dv/dx is -ve
and x and v is +ve as they r in 1st quad
So a=vdv/dx
Hence a is -ve and x is +ve from given graph

D is correct ๐Ÿ’ฏ

Sarthak-dlxs
ะะฒั‚ะพั€

Question 1) 4:31
Question)2) 8:54
Question 3) 11:46
Question 4) 16:20
Question 5) 21:57
Question 6) 31:02
Question 7) 36:43
Question 8) 41:17
Question 9) 44:04
Question 10) 46:06

Ankit-ryqd
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How easy life becomes when there is no choice left ๐Ÿ’”

cengageacademy
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This is the Last chance to crack JEE mains 2023 ๐Ÿ”ฅ otherwise you have to wait for JEE 2024 ๐Ÿ˜ถ

Krishna.Kumar.
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Thanks for new course BOOSTER๐Ÿ’—๐Ÿ’—.
thanks PW team !!

cricket_hindi.
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Sir I would suggest you ki aap iss batch me sabse pehle 12th ke chapters kra dijiye...kyunki wo lectures hme boards me bhi kaam aajayenge...Nhi to abhi 11th ke chapters pe dhyan dene me problem aayegi..kyunki boards aachuke hai....please sir help in this

shailendrakumar-gxrt
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Imp ques
11:46
16:19
21:57
31:02
43:59
46:44
52:28
1:17:40
1:22:40
1:26:20
1:34:33

Lazier___one
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Love you sir
Thanks for this series ๐Ÿ˜

aloksingh
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This question 1:21:21 can also be done by using the concept of (-b/2a, -D/4a) to find H max.

MSMINDIA
ะะฒั‚ะพั€

LAST QUES OPTION C) 15 m
#99%tile IN 2nd ATTEMPT ๐ŸŽฏ

sujatrabiswas